Initial values 0.25 kg, 0.4 kg, 0 m/s After collision 0.25kg, 1.5 m/s, A degrees 0.4 kg, B m/s, AA degrees 2 m/s, 0 degree Energy loss = 0.04 Joules Show the graph for momentum conservation equation in the horizontal direction with A degree as x-axis, C degrees as y-axis. On the same graph, plot the momentum conservation equation in the vertical direction Use the intersection point to find the values of A degrees, AA degrees, and B m/s.
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- A 2280kg truck traveling north at 44 km/h turns east and accelerates to 65 km/h. (a) What is the change in the truck's kinetic energy? (b) What is the magnitude of the change in its momentum? State correct units.A 50-g ball is shot into a chamber attached to a 500-g cart. After the collision the ball/cart combination moves away with a speed of 3.0 m/s. Assuming that friction and air resistance are negligible, determine the amount of energy lost in the collision.A 20 kg block with a speed of 10m/s collides with a 4kg block that has a speed of 5m/s in the same direction. After the collision, the 4 kg block travels in the original direction with a speed of 7 m/s (a) What is the velocity of the 20 kg block immediately after the collision? (b) By how much does the total kinetic energy of the system of two blocks change because of the collision? (c) Suppose, instead, that the 4kg block ends up with a speed of 8 m/s What then is the change in the total kinetic energy?
- Question 6. A diagram of the collision between a moving cue ball and an initially stationary eight ball on a billiards table is given below. The collision of the billiards balls can be considered an isolated system. W- N por Cue ball y = 4.00 m/s m = 0.180 kg p = 0.720 kg-m/s V 2/1 Apple 1₂V/2 0 DALO TO 4MB x V q Determine the velocity of the cue ball immediately after the collision. x 000000 m = 0.180 kg Eight ball O +0 40° ********** Question 7. Classify the collision above as elastic, inelastic or super elastic. dlad V = 3.20 m/s m = 0.160 kg p=0.512 kg-m/s AYP SOL CANDIDA * 12 2 no thouse 52a 600 gram banana sliding north on a frictionless table at 2.5 meters per second bounces of a 400 gram kiwi fruit that is initially at rest , after colliding the banana continues moving north at 0.5 meters per second. At the North edge of the track is a frictionless inclined ramp which the kiwi fruit slides up to then the kiwi comes back down the ramp , without losing energy , and will now be moving south , the kiwi will catch up and hit the banana again. How much momentum did the kiwi have just before the sticky collision ? how much just after ? how much did the kiwis momentum change ?Consider the head-on collision of two identical bowling balls, each with mass 5 kg (see figure). Ball A with velocity v = m/s strikes ball B, which was at rest. Then ball A stops and ball B moves with the same velocity v that ball A had initially. M M В Initially at rest Initial state (before collision) Final state (after collision) M M B Now at rest (a) Choose a system consisting only of ball A. What is the momentum change of the system during the collision? Apsystem = kg • m/s What is the momentum change of the surroundings? Apsurroundings = kg • m/s (b) Choose a system consisting only of ball B. What is the momentum change of the system during the collision? Apsystem = kg · m/s What is the momentum change of the surroundings? Apsurroundings = kg · m/s (c) Choose a system consisting of both balls. What is the momentum change of the system during the collision? APsystem = kg · m/s What is the momentum change of the surroundings? Apsurroundings = kg • m/s
- A billiard ball moving at 5.20 m/s strikes a stationary ball of the same mass. After the collision, the first ball moves at 4.67 m/s at an angle of 26.0° with respect to the original line of motion. Assuming an elastic collision (and ignoring friction and rotational motion), find the struck ball's velocity after the collision. magnitude direction 1.56 × Check the initial and final kinetic energies. You will find that your final kinetic energy is not equal to the initial kinetic energy. m/s ° (with respect to the original line of motion)a 600 gram banana sliding north on a frictionless table at 2.5 meters per second bounces of a 400 gram kiwi fruit that is initially at rest , after colliding the banana continues moving north at 0.5 meters per second. At the North edge of the track is a frictionless inclined ramp which the kiwi fruit slides up to then the kiwi comes back down the ramp , without losing energy , and will now be moving south , the kiwi will catch up and hit the banana again. If the last collision took 20 milliseconds , what was the average force exerted by the banana on the kiwi during the collision (magnitude and direction ) ? by the kiwi on the banana?A 2 kg object moving at 3 m/s collides with a 4 kg object that is stationary. If the collision is perfectly inelastic, what is the speed of the 2 kg object after the collision? and how much is KE lost? A) speed = 1.5 m/s and KE lost = 12J B) speed = -0.5 m/s and KE lost = 9J No answer speed = -1 m/s and KE lost = 3J E) speed = 1 m/s and KE lost = 6J %3D