Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
Related questions
Question
![Predict the equilibrium concentration of IBr in the reaction described below (for which Kc =
280 at the reaction temperature) by constructing an ICE table, writing an equilibrium
expression for Kc, and solving for the equilibrium concentration. Complete Parts 1-3
before submitting your answer.
NEXT >
In a 3.0 L container at high temperature, 0.400 mol of IBr is allowed to reach equilibrium. Fill in the ICE table
with the appropriate value for each involved species to determine the partial pressures of all reactants and
products. Where applicable, use the x variables to represent any unknown change in concentration.
Initial (M)
Change (M)
Equilibrium (M)
0.400 + x
0
0.400 + 2x
1
12(g) + Br₂(g) = 2 IBr(g)
1₂(g)
0.400
0.400 - x
0.133
0.400-2r
2
+
+X
0.133 + x
Br₂(g)
+2x
0.133 + 2x
3
-X
0.133 - x
2 IBr(g)
RESET
-2x
0.133 - 2x](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F19cce641-b997-49dc-afd2-8bab9dcfc62b%2F42b71377-7204-4fbe-8eba-2693d14d88c2%2Fdrbqt2d_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Predict the equilibrium concentration of IBr in the reaction described below (for which Kc =
280 at the reaction temperature) by constructing an ICE table, writing an equilibrium
expression for Kc, and solving for the equilibrium concentration. Complete Parts 1-3
before submitting your answer.
NEXT >
In a 3.0 L container at high temperature, 0.400 mol of IBr is allowed to reach equilibrium. Fill in the ICE table
with the appropriate value for each involved species to determine the partial pressures of all reactants and
products. Where applicable, use the x variables to represent any unknown change in concentration.
Initial (M)
Change (M)
Equilibrium (M)
0.400 + x
0
0.400 + 2x
1
12(g) + Br₂(g) = 2 IBr(g)
1₂(g)
0.400
0.400 - x
0.133
0.400-2r
2
+
+X
0.133 + x
Br₂(g)
+2x
0.133 + 2x
3
-X
0.133 - x
2 IBr(g)
RESET
-2x
0.133 - 2x
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