Figure 3. Inelastic Collision between carts of different masses and equal but oppositevelocities.cart#1cart#27562.55037.52512.50- 12.5-25125112.510087.57562.55037.5250position x(t)beforeafter50501001001.510.50-0.5-1-15-21.510.50-0.5-1-15velocity v(t)before5050aftertime (arb. units)10010021510.50-0.5-1-15-210.50-0.5- 1-1.5-2-2.5-300momentum p(t)beforeafter5050100100Also show total momentum inthe momentum graph for Cart #2 Inelastic Collision between carts of different masses and equal butopposite velocitiesRefer to figure 3. In this example, the masses of the two carts are againunequal, or m₁=1 unit, m₂=2 units. We turn the carts loose at their ends ofthe track with equal, but opposite velocities, or v₁=1 unit and v₂= -1 unit.Assume that the collision is inelastic (the carts stick together after colliding),consult eq. 5, complete the graph and describe the motion after thecollision.

Answered: Image /qna-images/answer/48b4ec7f-c476-46c0-a966-433ab52624fd.jpg

Inelastic Collision between carts of different masses and equal but opposite velocities Refer to figure 3. In this example, the masses of the two carts are again unequal, or m₁=1 unit, m²=2 units. We turn the carts loose at their ends of the track with equal, but opposite velocities, or V₁=1 unit and v₂= -1 unit. Assume that the collision is inelastic (the carts stick together after colliding), consult eq. 5, complete the graph and describe the motion after the collision.

Inelastic Collision between carts of different masses and equal but opposite velocities Refer to figure 3. In this example, the masses of the two carts are again unequal, or m₁=1 unit, m²=2 units. We turn the carts loose at their ends of the track with equal, but opposite velocities, or V₁=1 unit and v₂= -1 unit. Assume that the collision is inelastic (the carts stick together after colliding), consult eq. 5, complete the graph and describe the motion after the collision.

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

See similar textbooks

Similar questions

Please answer in full decimal places
tion 4 of 9 Two particles approach each other with equal and opposite speed, v. The mass of one particle is m, and the mass of the other particle is nm, where n is just a unitless number. Snapshots of the system before, during, and after the elastic collision are shown. Before Collision Aftér m nm m nm Vn.final nm,final After the collision, the first particle moves in the exact opposite direction with speed 1.30v, and the speed of the second particle, Unm,final , is unknown. What is the value of n? n =
Hockey players "Betty" and "Sally" collide as they race to reach the hockey puck. The figure shows speed and direction before the collision, as well as the direction after the collision. Betty's mass is 55.0 kg, and Sally's mass is 45.0 kg. c) Calculate the speed of both Betty and Sally after the collision. Was the collision elastic? d) What was the force impulse on Betty (value and direction) in the collision?
MO-6 The Meteor Crater in Arizona is about 1,200m wide and 200m deep. It is believed to have been formed 20,000 years ago when a meteor with a mass of 5.0x10"kg moving at 7.2km/s collided and merged with the earth. If the earth had been at rest prior to the collision, what would the speed of the earth have been after this collision? The mass of the earth is 5.98x10"kg. 24
Based on the principle conservation of linear momentum, which statement is true ? (Ma and Mp are masses of two objects a and b. Vaj and Vb; are the initial velocities of Mą and Mp respectively before collision. Vaf and Vbf are the final velocities of Ma and Mp respectively after collision.) MaVbit MoVai =MaVbpt MoVas None of the options available MVai + MBVbi = MVaf + MpVbf MaVai+MpVbf=MaVaf+ MbVbi MaVai+ MaVas=MBVbi+ MbVbf
A golf ball is moving at speed vo to the East. After deflecting off a tree, it moves at a speed of 0.90vo in a direction which is 25° North of East. Check all the following answers which are true statements. There may be more than one correct answer! The impulse vector (delivered by the tree) has components which point North and West The ball's momentum vector has the same magnitude before and after the collision The impulse vector (delivered by the tree) points purely to the North The ball's momentum vector decreases in magnitude during the collision
A point particle of mass 3.9 kg is moving with an initial velocity of 2.27 m/s i. It collides and sticks to an object of mass 4.16 moving at velocity of -1 m/s j before collision. What is the speed of the particles after collision? Express your answer in m/s and with two decimal places.
(Please include diagram or drawing) Two clay meteors, each with a mass m, collide in outer space and stick together. This collision occurs at a distance D from the center of the Earth. Following the collision, the combined meteors move towards the Earth. Before the collision: Meteor 1 has a velocity v1. Meteor 2 has a velocity v2. The velocities V1 and v2 are at right angles to each other. a) Calculate the fraction of kinetic energy lost during the collision of the two meteors. b) Determine the velocity of the stuck-together meteors just before they crash into the Earth assuming you know the mass and radius of earth. Air resistance can be neglected.
A body with mass of 5 kg is moving at a speed of 2 m/s and collides inelastically with another body with mass of 3 kg that stayed at rest before the collision. What speed will the bodies have after the collision?
Two objects, A and B, have the same mass move in an opposite direction and collide with each other. A moves east a speed of V and B move west at a speed of 2V. If the collision is perfectly elastic, then what is the velocity of both objects after the collision.
Two blocks with masses 5m and 8m are on a collision course with the same initial speeds v;. The block with mass 5m is traveling to the left, and the 8m block is traveling to the right. They undergo a head-on elastic collision and each bounces back, retracing its original path. Find the final speeds of the particles. (Enter your answers in terms of v, the initial speed of each mass.) V 5m,f Vsm,f Vi
please help me with this problem. Given: A ball of clay mass M/8 A larger mass as known as M is attached to a spring with spring constant k. A ball of clay mass "M/8" moves with speed "v" towards a larger mass M. As the a ball of clay hit and sticks on the a larger mass who was initially still. a) What would be the speed of the combination after the collision? b) How much did the spring compressed c) How long did it take for the spring to be compressed due to the collision?