im not sure how to do the percent difference, and also the solpe= bl/r thank you Data Table 1.B =619L =194mmR =7.1ohmDisplacement, Average Velocity, Induced Current,Elapsed Time,At(ms)RunAX(cm)(m/s)(mA)165.0365.549358.1366.20105354.3366.63114450.1367.1911946.3367.78127643.5368.28137742.1368.55114839.4369.14154938.0369.47164 Induced Current Vs. Average Velocity135137130125LINEAR120X-range: 5.54 - 8.28 vy mx + b115m: 15.31b: 9.667110r:0.9941RMSE: 1.898105100956.06.57.07.58.08.28Average Velocity (m/s) ()13.0you dohave a linear trendline equation for this graph, then compare the slope ofBLyour graph to the following equation, slopeAre these values the sameRor not? Not the same.14. This time we will be using the formula for percent difference, shown below, tofind out how close your two values are. Then you may proceed to the nextlab procedure. Please show all your calculations and all your units work inyour lab submission!!|Value1 – Value2|%difference =-× 100%(Value1 + Value2yInduced Current I (mA)

This is an experimental procedure with the aim of comparing the p value obtained from the experiment…

Answered: Induced Current Vs. Average Velocity…

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