Which of the following is not a base unit in 0/6 the decimal system. m kg S N cd
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- How many significant figures are in each of the following? a) 2.401 b) 0.0005337 c) 6.00 d) 5.1 x 105 e) 0.133The sides of a small rectangular box are measured to be (1.90 ± 0.01) cm, (2.00 ± 0.02) cm, and (3.1 ± 0.1) cm long. Calculate its volume and uncertainty in cm³. a. Its volume is b. The uncertainty on its volume is cm³. cm³.What is the area of a circle which has a diameter equal to 3.138 cm? Hint The area is cm².
- s is a distance with unit [L], t is a time with unit [T] and θ is an angle in radians. a. Find the dimensions for the quantity c2 in the expression s = c2t2. b. Find the dimensions for the quantity c3 in the expression s = c3cos(c4t). c. Find the dimensions for the quantity c4 in the expression s = c3cos(c4t). d. Find the dimensions for the quantity c5 in the expression θ = s / c5.Soccer fields vary in size. A large soccer field is 144 meters long and 84.4 meters wide. Hint a. What are its dimensions in feet? o Its length is ft. o Its width is b. What are its dimensions in inches? o Its length is o Its width is ft. in. in.Q1) A) Find the answers to the following problems using the rule of Significant Figures a) (10.4168) m - (6.0) m b) (1.31) ст х (2.3) сm c) (5.7621) m / (6.201) m d) (2.5000) m + (32.85) m B) Represent each answer above in the scientific notation
- Practice) a. To convert feet (ft) to meters (m), the number of feet should be multiplied by which of the following conversion factors? i. 1 m/3.28 ft ii. 3.28 ft/1 m b. To convert sq.in to sq.ft, the number of sq.in should be multiplied by which of the following conversion factors? i. 144 sq.in/1 sq.ft ii. 1 sq.ft/144 sq.in c. To convert sq.yd to sq.ft, the number of sq.yd should be multiplied by which of the following conversion factors? i. 1 sq.yd/9 sq.ft ii. 9 sq.ft/1 sq.yd 3. (Practice) Determine the final units of the following expression: 9.8m/s2 ×100cm/1m×1in/2.54cm×1ft/12in 4. (Practice) a. Determine the conversion factors that can be used to convert miles per gallon (mpg = mi/gal) to kilometers per liter (km/liter), given that 1 liter = 0.22 gallons and 1 kilometer = 0.6214 miles. b. Using the conversion factors you determined in Exercise 4a, convert 25 mpg into km/liter. 5. (Automotive) a. An automobile engine’s performance can be determined by monitoring its rotations per…Can i get help with these problems pleaseil vidong P 7. (10pt) In AABC, ZC = 81°, ZB = 33°, and side c = 15. Find side b of AABC to the nearest tenth. pucg 1701 8. (a) (5pt) Prove the identity: secx-cosx = secx sin²x Ils obulout jollood moitotumnez baicoibai saiwisdio aeslau mmol jalgraiz oszo ni flot bris bolodal (b) (5pt) Find cos, if sin and tan 0 <0 5 snowers odriguia bustolovioc (0.x) mpl ori) to anotulos) airpori y bris x sit state noitsupo ostboup grivollol smil movie (inc E+xxx dgety od dolose or noemolni zid sau no bas tev dr.((,0) bas 9. Find all exact solutions to the trig equations for x = [0, 27): tan(x) = -√3 2 sin(x) = √2 (a) (5pt) (b) (5pt) =-- 10. (a) (5pt) Evaluate the logarithm without using a calculator: log, (819) hoitoup oils bri (b) (5pt) Solve for x and round the answer to the nearest tenth: 12* = 384 110 auibet bos.odnos odi vinobl mol bisbraste 20180b7009 diw storio edino ziniog spot fods. I npitori xalqinos oli vulgrai? woled invig oloro od to noisups silloi odi gniau slonio odi dgers bi 01-…
- A new unit of measurement for long distances is introduced by superheroes into the scientific community. Convert 8.5 starks into feet. 115 stark = 29 Kent EXACT 13 Kent = 35 feet EXACTThe number of significant digits is set to 2Newton's universal law of gravitation can be stated as the force F of gravitation between two objects varies jointly as the masses m, and m, of the objects, and Gm,m2 inversely as the square of the distance r between their centers, where G is the constant of proportionality. In other words, F = The weight of an object is the force F on the object due to gravity, where F = mg. State how g (the acceleration due to gravity) varies with respect to the mass m, of the spherical body on which the object lies, and the radius of that body (assume all of the mass is at its center.). The acceleration due to gravity, g, varies as the spherical body's mass, and as