Indicate the oxidation state of every individual element in the following compounds. Fractional oxidation states are acceptable. d. Na,C,O4 h. SO3 f. H.СО

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**Oxidation States of Elements in Compounds**

In this section, we will determine the oxidation state of each individual element in the given compounds. Fractional oxidation states are acceptable.

**d. Na₂C₂O₄ (Sodium Oxalate)**

1. Sodium (Na):
   - Sodium is an alkali metal and typically has an oxidation state of +1.
   - Since there are two sodium atoms, the total oxidation state from sodium is +2.
2. Carbon (C):
   - Let the oxidation state of carbon be \( x \).
3. Oxygen (O):
   - Oxygen typically has an oxidation state of -2.
   - Since there are four oxygen atoms, the total oxidation state from oxygen is -8.

The sum of oxidation states in Na₂C₂O₄ should equal zero (assuming the compound is neutral).

\[ 2(+1) + 2(x) + 4(-2) = 0 \]
\[ 2 + 2x - 8 = 0 \]
\[ 2x - 6 = 0 \]
\[ 2x = 6 \]
\[ x = +3 \]

Thus, the oxidation state of carbon (C) in Na₂C₂O₄ is +3.

**f. H₂CO (Formaldehyde)**

1. Hydrogen (H):
   - Hydrogen typically has an oxidation state of +1.
   - Since there are two hydrogen atoms, the total oxidation state from hydrogen is +2.
2. Carbon (C):
   - Let the oxidation state of carbon be \( x \).
3. Oxygen (O):
   - Oxygen typically has an oxidation state of -2.

The sum of oxidation states in H₂CO should equal zero (assuming the compound is neutral).

\[ 2(+1) + x + (-2) = 0 \]
\[ 2 + x - 2 = 0 \]
\[ x = 0 \]

Thus, the oxidation state of carbon (C) in H₂CO is 0.

**h. SO₃ (Sulfur Trioxide)**

1. Sulfur (S):
   - Let the oxidation state of sulfur be \( x \).
2. Oxygen (O):
   - Oxygen typically has an oxidation state of -2.
   - Since there are three oxygen atoms, the total oxidation state from oxygen is -6.

The sum of oxidation states in
Transcribed Image Text:**Oxidation States of Elements in Compounds** In this section, we will determine the oxidation state of each individual element in the given compounds. Fractional oxidation states are acceptable. **d. Na₂C₂O₄ (Sodium Oxalate)** 1. Sodium (Na): - Sodium is an alkali metal and typically has an oxidation state of +1. - Since there are two sodium atoms, the total oxidation state from sodium is +2. 2. Carbon (C): - Let the oxidation state of carbon be \( x \). 3. Oxygen (O): - Oxygen typically has an oxidation state of -2. - Since there are four oxygen atoms, the total oxidation state from oxygen is -8. The sum of oxidation states in Na₂C₂O₄ should equal zero (assuming the compound is neutral). \[ 2(+1) + 2(x) + 4(-2) = 0 \] \[ 2 + 2x - 8 = 0 \] \[ 2x - 6 = 0 \] \[ 2x = 6 \] \[ x = +3 \] Thus, the oxidation state of carbon (C) in Na₂C₂O₄ is +3. **f. H₂CO (Formaldehyde)** 1. Hydrogen (H): - Hydrogen typically has an oxidation state of +1. - Since there are two hydrogen atoms, the total oxidation state from hydrogen is +2. 2. Carbon (C): - Let the oxidation state of carbon be \( x \). 3. Oxygen (O): - Oxygen typically has an oxidation state of -2. The sum of oxidation states in H₂CO should equal zero (assuming the compound is neutral). \[ 2(+1) + x + (-2) = 0 \] \[ 2 + x - 2 = 0 \] \[ x = 0 \] Thus, the oxidation state of carbon (C) in H₂CO is 0. **h. SO₃ (Sulfur Trioxide)** 1. Sulfur (S): - Let the oxidation state of sulfur be \( x \). 2. Oxygen (O): - Oxygen typically has an oxidation state of -2. - Since there are three oxygen atoms, the total oxidation state from oxygen is -6. The sum of oxidation states in
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