Question 7 **Transcription for Educational Website**---**Exercise: Indicate the Major Organic Product**In the reaction shown, identify the major organic product that results.**Reaction Diagram:**- **Reactant Molecule:** The reactant is a six-carbon chain with a ketone group (C=O) located on the third carbon from the left. - **Reagent:** Sodium ethoxide (NaOCH₂CH₃) is used as the reagent.**Reaction Arrow:** The arrow indicates the direction of the chemical reaction from the reactant, under the conditions provided by the reagent, towards the major organic product.Note: In this reaction, sodium ethoxide typically acts as a strong base in deprotonation reactions, which may lead to the formation of an enolate ion, subsequent alkylation, or other transformations. Consider the typical reactivity and mechanisms associated with ketones and enolates.---

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Science

Chemistry

Indicate the major organic product from the reaction shown. NaOCH2CH3

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Concept explainers

Diol

In chemistry there are so many chemical compounds that have a hydroxyl group but a chemical compound having two hydroxyl groups (-OH) is termed as a diol. It also implies the presence of two alcohols whereas polyols contain two or more than two hydroxyl groups (-OH). Glycol or 1,2-diol is an aliphatic diol that has two alcohol groups on adjacent carbon atoms. In industries, the most commonly used diol is ethylene glycol.

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Question 7

**Transcription for Educational Website**

---

**Exercise: Indicate the Major Organic Product**

In the reaction shown, identify the major organic product that results.

**Reaction Diagram:**

- **Reactant Molecule:** The reactant is a six-carbon chain with a ketone group (C=O) located on the third carbon from the left.

- **Reagent:** Sodium ethoxide (NaOCH₂CH₃) is used as the reagent.

**Reaction Arrow:** The arrow indicates the direction of the chemical reaction from the reactant, under the conditions provided by the reagent, towards the major organic product.

Note: In this reaction, sodium ethoxide typically acts as a strong base in deprotonation reactions, which may lead to the formation of an enolate ion, subsequent alkylation, or other transformations. Consider the typical reactivity and mechanisms associated with ketones and enolates.

---

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