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Independent random samples were selected from two quantitative populations, with sample sizes, means, and standard deviations given below. n₁ = n₂ = 70, x₁ = 125.3, x₂ = 123.8, s₁ = 5.9, S₂ = 6.1 Construct a 95% confidence interval for the difference in the population means (₁-₂). (Round your answers to two decimal places.) -0.5 X to 3.5 X Find a point estimate for the difference in the population means. 1.5 Calculate the margin of error. (Round your answer to two decimal places.) 2.00

Independent random samples were selected from two quantitative populations, with sample sizes, means, and standard deviations given below. n₁ = n₂ = 70, x₁ = 125.3, x₂ = 123.8, s₁ = 5.9, S₂ = 6.1 Construct a 95% confidence interval for the difference in the population means (₁-₂). (Round your answers to two decimal places.) -0.5 X to 3.5 X Find a point estimate for the difference in the population means. 1.5 Calculate the margin of error. (Round your answer to two decimal places.) 2.00

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
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**Statistical Analysis of Sample Data** **Independent Random Samples:** Two independent random samples were selected from two quantitative populations. The following statistical measures were provided: - Sample Size for both samples: \( n_1 = n_2 = 70 \) - Mean of Sample 1: \( \bar{x}_1 = 125.3 \) - Mean of Sample 2: \( \bar{x}_2 = 123.8 \) - Standard Deviation of Sample 1: \( s_1 = 5.9 \) - Standard Deviation of Sample 2: \( s_2 = 6.1 \) **Tasks and Solutions:** 1. **Construct a 95% Confidence Interval:** - A confidence interval was calculated for the difference in the population means (\( \mu_1 - \mu_2 \)). - The interval provided was from -0.5 to 3.5; however, this solution was marked with an "X", indicating an incorrect response. 2. **Point Estimate for the Difference:** - The calculated point estimate for the difference in the population means was given as 1.5, which was marked with a check, indicating it was correct. 3. **Calculate the Margin of Error:** - The margin of error was calculated as 2.00, but this solution was marked with an "X", indicating it was incorrect. This exercise demonstrates how to calculate confidence intervals and point estimates, along with the determination of margin of error for population mean differences using sample data.
Transcribed Image Text:**Statistical Analysis of Sample Data** **Independent Random Samples:** Two independent random samples were selected from two quantitative populations. The following statistical measures were provided: - Sample Size for both samples: \( n_1 = n_2 = 70 \) - Mean of Sample 1: \( \bar{x}_1 = 125.3 \) - Mean of Sample 2: \( \bar{x}_2 = 123.8 \) - Standard Deviation of Sample 1: \( s_1 = 5.9 \) - Standard Deviation of Sample 2: \( s_2 = 6.1 \) **Tasks and Solutions:** 1. **Construct a 95% Confidence Interval:** - A confidence interval was calculated for the difference in the population means (\( \mu_1 - \mu_2 \)). - The interval provided was from -0.5 to 3.5; however, this solution was marked with an "X", indicating an incorrect response. 2. **Point Estimate for the Difference:** - The calculated point estimate for the difference in the population means was given as 1.5, which was marked with a check, indicating it was correct. 3. **Calculate the Margin of Error:** - The margin of error was calculated as 2.00, but this solution was marked with an "X", indicating it was incorrect. This exercise demonstrates how to calculate confidence intervals and point estimates, along with the determination of margin of error for population mean differences using sample data.
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