How could you solve this? Independent random samples of professional football and basketball players gave the following information. Assume that the weight distributions are mound-shaped and symmetric.Weights (in Ib) of pro football players: x1; n1 = 21248 261 255 251 244 276 240 265 257 252 282256 250 264 270 275 245 275 253 265 271Weights (in Ib) of pro basketball players: x2; n2 = 19205 200 220 210 192 215 223 216 228 207225 208 195 191 207 196 181 193 201(a) Use a calculator with mean and standard deviation keys to calculate x1, S1, X2, and s3. (Round your answers to one decimal place.)X1 =S1 =X2 =S2 =(b) Let 41 be the population mean for x1 and let u2 be the population mean for x2. Find a 99% confidence interval for u1 - H2: (Round your answers to one decimal place.)lower limitupper limit

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Description: How could you solve this? Independent random samples of professional football and basketball players gave the following information. Assume that the weight distributions are mound-shaped and symmetric.Weights (in Ib) of pro football players: x1; n1 =

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MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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How could you solve this?

Independent random samples of professional football and basketball players gave the following information. Assume that the weight distributions are mound-shaped and symmetric.
Weights (in Ib) of pro football players: x1; n1 = 21
248 261 255 251 244 276 240 265 257 252 282
256 250 264 270 275 245 275 253 265 271
Weights (in Ib) of pro basketball players: x2; n2 = 19
205 200 220 210 192 215 223 216 228 207
225 208 195 191 207 196 181 193 201
(a) Use a calculator with mean and standard deviation keys to calculate x1, S1, X2, and s3. (Round your answers to one decimal place.)
X1 =
S1 =
X2 =
S2 =
(b) Let 41 be the population mean for x1 and let u2 be the population mean for x2. Find a 99% confidence interval for u1 - H2: (Round your answers to one decimal place.)
lower limit
upper limit

Expert Solution

Step 1

(a)

Mean and standard deviation for $x_{1}$ :

Use Ti 83 calculator to find the mean and standard deviation as follows:

Select STAT > Edit > Enter the values of as L1.
Click $2^{n d}$ button; STAT; take the arrow to the MATH menu, and then ‘3’ numbered key.
Click $2^{n d}$ button; then ‘1’ numbered key to get L1, and close the ‘)’ bracket.
Click Enter.
Click $2^{n d}$ button; STAT; take the arrow to the MATH menu, and then ‘7’ numbered key.
Click $2^{n d}$ button; then ‘1’ numbered key to get L1, and close the ‘)’ bracket.
Click Enter.

Output using Ti 83 calculator is given below:

From the Ti 83 calculator output, the mean value is 259.8, and standard deviation value is 11.9.

Thus, ${\bar{x}}_{1} = 259.8, s_{1} = 11.9$ .

Mean and standard deviation for $x_{2}$ :

Use Ti 83 calculator to find the mean and standard deviation as follows:

Select STAT > Edit > Enter the values of as L2.
Click $2^{n d}$ button; STAT; take the arrow to the MATH menu, and then ‘3’ numbered key.
Click $2^{n d}$ button; then ‘2’ numbered key to get L2, and close the ‘)’ bracket.
Click Enter.
Click $2^{n d}$ button; STAT; take the arrow to the MATH menu, and then ‘7’ numbered key.
Click $2^{n d}$ button; then ‘2’ numbered key to get L2, and close the ‘)’ bracket.
Click Enter.

Output using Ti 83 calculator is given below:

From the Ti 83 calculator output, the mean value is 205.9, and standard deviation value is 13.0.

Thus, ${\bar{x}}_{2} = 205.9, s_{2} = 13.0$ .

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