Increasing the likelihood to reject the null hypothesis is possible if: O We decrease the sample size to increase the power of the study O The magnitude of difference is small and negligible O The observed value is close to the true value in the population O The sum of squared distances of values is away from the mean is small
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- Serial Killers: Everything Up to One-Way Between-Groups ANOVA What analysis could be used to find out if the number of serial killers in the countries in North America is significantly different than in all the countries in the world? a. z test b. single-sample t test c. paired-samples t test d. independent-samples t test e. one-way between-groups ANOVAAn experiment wants to determine the impact of two inputs (X and Y) on the quantity of the good produced. The results from this experiment is shown in the table: Input X Input Y A B C 1 80 88 73 2 87 83 83 3 90 93 79 State the null hypothesis for this study (in words) Calculate all the sum of squared deviations for the experiment. Calculate all the mean of squared deviations for the experiment. Calculate the relevant F-statistics. Using a significance level of 5% what conclusions would you draw from the study?There are four questions about this problem in the test shown in random order. Out of 1000 customers in the test data, there are only 100 buyers. A classification model applied to these customers, predicts 200 buyers. If buying is regarded as positive, there are 50 true positives. What is precision? a. 10% O b. 25% 20% O d. 50%
- Identify test statistic Identify Z value Reject or accept hypothesisAssume that a simple random sample has been selected from a normally distributed population. Identify the null hypothesis, alternative hypothesis, test statistic, P-value ( or range of P-value), critical value(s), conclusion about the null hypothesis, and final conclusion that addresses the original claim. Listed below are measured amounts of lead (in micrograms per cubic meter, or μ g/m 3 ) in the air. 5.40 1.10 0.42 0.73 0.48 1.10 0.89 1.29 Use a 0.01 significance level to test the claim that the sample is from a population with a mean greater than 1.5 μ g/m 3.For the last sentence / first blank is choices in/not in . second blank is fail to reject/ reject third blank is is not /is
- Test the indicated claim about the means of two populations. Assume that the two samples are randomly selected, independent, the population standard deviations are not know and not considered equal. Two types of cereal ? are test for their consumption time (in minutes). At the 0.01 significance level, test the claim that the two populations of cereal have equal means. Cereal A Cereal B n1 = 37 n2 = 35 xˉx̄1 = 19.6 min xˉx̄2 = 19.1 min s1 = 1.7 min s2 = 0.6 min What are the correct hypotheses? (Select the correct symbols and use decimal values not percentages.)H0: Select an answer p₁ x̄₁ μ₂ p̂₁ x̄₂ μ μ(A) p s₁² p₂ σ₁² μ₁ ? > ≥ ≤ < = ≠ Select an answer μ(B) p₁ p p₂ x̄₂ μ x̄₁ s₁² μ₂ μ₁ p̂₁ σ₁² H1: Select an answer σ₂² μ₂ x̄₁ p̂₂ p₁ μ₁ s₂² x̄₂ μ μ(A) p₂ p ? > = ≠ ≥ ≤ < Select an answer p₁ p μ₂ s₁² μ₁ x̄₁ p̂₁ p₂ μ(B) σ₁² μ x̄₂ Original Claim = Select an answer H₁ H₀ df = Based on the hypotheses, find the following: Test Statistic = (Round to three decimal…Test the claim about the difference between two population means P, and p2 at the level of significance a. Assume the samples are random and independent, and the populations are normally distributed. Population statistics: o, = 3.5, o2 = 1.3 Sample statistics: x, = 16, n, =28, X2 = 14, n2 = 30 Determine the alternative hypothesis. Determine the standardized test statistic. (Round to two decimal places as needed.) Determine the P-value. P-value = (Round to three decimal places as needed.) What is the proper decision? O A. Fail to reject Ho. There is not enough evidence at the 1% level of significance to reject the claim. O B. Fail to reject Ho. There is enough evidence at the 1% level of significance to reject the claim. O C. Reject Ho. There is enough evidence at the 1% level of significance to reject the claim. O D. Reject Ho. There is not enough evidence at the 1% level of significance to reject the claim.Can I get some assistance with these true and false questions please, no explanation needed. True or false? A. The multiplication rule in probability allows for two events that can occur simultaneously B.The one way anova is constructed around the concept of determining goodness of fit between explanatory and outcome variable. C.The strength of association between two continuous variable can be determined by the correlation coefficient D.Z scores facilitate the proportional determination of a sample into segmental capture of accuracy and precision in data measurement. E. The chi-square allows for the use of expected data to be contrasted with observed data points F. Association between two categorical variables can be determined by simple linear regression. G. One can say that the regression and anova seem to be related because of the idea of finding the best fit for the data. H. The spread of the data which determines the error in the groups and between the groups is calculated by the…
- A significance test is based on the following idea: Make an assumption about the population (The null hypothesis an assumption that the parameter equals a value). Then test to see if, under the assumption that the null hypothesis is true how likely is the sample that you got? If the sample you got is likely (within the range of normal defined by o or with probability greater then o) then it is possible that both the sample and the null hypothesis is true. If the sample is not likely then both it and the null hypothesis are probably not both true. Since the sample was collected (under the assumption it was collected well) then the null hypothesis is probably not true and we reject the null hypothesis. There are 3 types of significance tests. Left-sided test: Unusual defined by the test statistic being less than the critical value which cuts off or area in the left tail (note these will be negative values, less then means bigger negative) or a p-value less then a, where p-value is the…Prices and mileage of 44 Toyota Prius cars. Prices ranged from $17,043 to $48,935. Mileage ranged from 403 to 70,838. While I did not share the cars were 2017 to 2020 models. Please show all work. Does this model meet the Normality assumption? Provide evidence and a discussion of support for meeting the assumption. Does this model meet the Equal Variance (Homoscedasticity) assumption? Provide evidence and a discussion of support for meeting the assumption. Price Mileage 17167 67380 24500 8137 20700 14907 20700 13906 18995 39268 21985 3292 19995 32630 19983 36074 19477 35484 20980 23954 24940 7001 24940 7991 25480 3476 17960 41051 25980 403 24500 8137 18588 66109 18788 51022 19200 32753 21985 38838 24512 2307 22997 33671 18480 27233 18480 27758 17043 70838 17761 21967 18488 11686 17793 26080 17900 36655 18100 46264 20500 27112 22410 17384 22817 2860 21660 17060 17575 54848 20250 21084 20259 21183…give clean answer handwritten clear picture and correct n detailed answer