Increasing the concentration of a product in a system Decreasing the concentration of a product in a system Adding heat to a system Reactants + heat Products

Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Reactants
Products
Change applied
Increasing the concentration
of a reactant in a system
Decreasing the concentration
of a reactant in a system
Increasing the concentration
of a product in a system
Decreasing the concentration
of a product in a system
Adding heat to a system
Reactants + heat Products
Adding heat to a system
Reactants Products + heat
Removing heat from a
system
Reactants + heat Products
Removing heat from a
system
Reactants Products + heat
Expected direction of shift
Shift right toward product
Shift is going be back to the
left or toward the reactant
Explanation
Because an increase in
reactant then the system
needs to adjust for
equilibrium by shifting to the
opposing side
Because now there is a
greater concentration of the
product and so the system
will adjust by moving toward
the downhill the side of the
reaction
Transcribed Image Text:Reactants Products Change applied Increasing the concentration of a reactant in a system Decreasing the concentration of a reactant in a system Increasing the concentration of a product in a system Decreasing the concentration of a product in a system Adding heat to a system Reactants + heat Products Adding heat to a system Reactants Products + heat Removing heat from a system Reactants + heat Products Removing heat from a system Reactants Products + heat Expected direction of shift Shift right toward product Shift is going be back to the left or toward the reactant Explanation Because an increase in reactant then the system needs to adjust for equilibrium by shifting to the opposing side Because now there is a greater concentration of the product and so the system will adjust by moving toward the downhill the side of the reaction
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