(Incorrect) For the reaction 2A(g) + B(s) C() + 2D(g) at 700 °C, Kc = 0.00577. Calculate the number of moles of D present at equilibrium if a mixture of 6.03 moles of C and 6.03 moles of D is heated to 700 °C in a 7.61-L container. 0.0074 mol (Your answer) 0.430 mol (Correct answer) 5.60 mol 0.056 mol

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For the reaction:

\[ 2A(g) + B(s) \rightleftharpoons C(l) + 2D(g) \]

at 700 °C, \( K_C = 0.00577 \). Calculate the number of moles of \( D \) present at equilibrium if a mixture of 6.03 moles of \( C \) and 6.03 moles of \( D \) is heated to 700 °C in a 7.61-L container.

- **0.0074 mol (Your answer)**
- **0.430 mol (Correct answer)**
- **5.60 mol**
- **0.056 mol**

Explanation: This problem involves calculating the equilibrium concentration of a product in a chemical reaction using the equilibrium constant \( K_C \) and initial conditions.
Transcribed Image Text:For the reaction: \[ 2A(g) + B(s) \rightleftharpoons C(l) + 2D(g) \] at 700 °C, \( K_C = 0.00577 \). Calculate the number of moles of \( D \) present at equilibrium if a mixture of 6.03 moles of \( C \) and 6.03 moles of \( D \) is heated to 700 °C in a 7.61-L container. - **0.0074 mol (Your answer)** - **0.430 mol (Correct answer)** - **5.60 mol** - **0.056 mol** Explanation: This problem involves calculating the equilibrium concentration of a product in a chemical reaction using the equilibrium constant \( K_C \) and initial conditions.
Expert Solution
Step 1: Introduction to the given data

The given equilibrium reaction is 

 2A(g) +B(s) rightwards harpoon over leftwards harpoonC(l) + 2D(g)

The equilibrium constant of the reaction, Kc = 0.00577 at 700 degree C

Number of moles of C = 6.03 mol

Number of moles of D = 6.03 mol

The volume of the container =7.61 L

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