(Incorrect) For the reaction 2A(g) + B(s) C() + 2D(g) at 700 °C, Kc = 0.00577. Calculate the number of moles of D present at equilibrium if a mixture of 6.03 moles of C and 6.03 moles of D is heated to 700 °C in a 7.61-L container. 0.0074 mol (Your answer) 0.430 mol (Correct answer) 5.60 mol 0.056 mol
(Incorrect) For the reaction 2A(g) + B(s) C() + 2D(g) at 700 °C, Kc = 0.00577. Calculate the number of moles of D present at equilibrium if a mixture of 6.03 moles of C and 6.03 moles of D is heated to 700 °C in a 7.61-L container. 0.0074 mol (Your answer) 0.430 mol (Correct answer) 5.60 mol 0.056 mol
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![For the reaction:
\[ 2A(g) + B(s) \rightleftharpoons C(l) + 2D(g) \]
at 700 °C, \( K_C = 0.00577 \). Calculate the number of moles of \( D \) present at equilibrium if a mixture of 6.03 moles of \( C \) and 6.03 moles of \( D \) is heated to 700 °C in a 7.61-L container.
- **0.0074 mol (Your answer)**
- **0.430 mol (Correct answer)**
- **5.60 mol**
- **0.056 mol**
Explanation: This problem involves calculating the equilibrium concentration of a product in a chemical reaction using the equilibrium constant \( K_C \) and initial conditions.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F6d7773ea-2418-45b6-94fc-b17f139a153f%2F0504a573-4842-4361-9173-50f6aa586adb%2Fgtkh0a_processed.jpeg&w=3840&q=75)
Transcribed Image Text:For the reaction:
\[ 2A(g) + B(s) \rightleftharpoons C(l) + 2D(g) \]
at 700 °C, \( K_C = 0.00577 \). Calculate the number of moles of \( D \) present at equilibrium if a mixture of 6.03 moles of \( C \) and 6.03 moles of \( D \) is heated to 700 °C in a 7.61-L container.
- **0.0074 mol (Your answer)**
- **0.430 mol (Correct answer)**
- **5.60 mol**
- **0.056 mol**
Explanation: This problem involves calculating the equilibrium concentration of a product in a chemical reaction using the equilibrium constant \( K_C \) and initial conditions.
Expert Solution

Step 1: Introduction to the given data
The given equilibrium reaction is
2A(g) +B(s) C(l) + 2D(g)
The equilibrium constant of the reaction, Kc = 0.00577 at 700
Number of moles of C = 6.03 mol
Number of moles of D = 6.03 mol
The volume of the container =7.61 L
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