An airline wants to select a computer software package for thereservation system. Four software packages (1,2,3,4) arecommercially available. The airline will choose the package thatbumps as few passengers, on average, as possible during a month.An experiment is set up in which each package is used to makereservations for 5 randomly selected weeks. A total of 20 weeks wasincluded in the experiment. The number of passengers bumped eachweek is obtained, which gives rise to the following output analysis asin Output 1. Based on Output 1, the among group mean squaresOutput 1ANOVASource of VariationBetween Groupsp-value8.304985 0.001474 3.238867dfMSF crit212.4Within Groups136.48.525Total348.88.52570.80212.4637.2

We have given that The sum of squares (SS) between groups = 212.4 The degrees of freedom between…

Answered: included in the experiment. The number…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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The manager of a political party wants to find out the association between the campaign spending (Large, medium and small) and the vote obtained (Majority, Average and minority). Use Chi-squared hypothesis test for association to test that there is an association between the variable in campaign spending and the variable in vote obtained with five percent level of significance. The manager uses MS excel to calculate the Chi-squared stat value and the result is 8.874. Critical value: At 1% = 13.277 :At 5% = 9.488 :At 10% = 7.779 1. State the decision rule 2. Conclusion and decision 3. State the alternative hypothesis and the null hypothesis
An experiment was carried out to compare the sound distortion produced by 4 different types of coating on magnetic tape. The ANOVA table for this data is given below, where X indicates a missing value. Source Degrees of Freedom Sum of Squares Mean Squares IF Treatment X 14.49 X Error X X X Total 49 165.69 Compute the F statistic. Give your answer to 2 decimal places.
The proprietor of a greenhouse claims that its pots of lilies average 6.0 buds, with s = 0.4 buds. If n = 29 pots of lilies from a large no of pots of lilies has a mean of 5.8 buds, does this deny the proprietor’s claim of the mean number of buds at 0.015 level of significance?
One important consideration in determining which location is best for a new retail business is the amount of traffic that passes the location each business day. Counters are placed at each of four locations on the five weekdays, and the number of cars passing each location is recorded in the table below. At 0.05 level of significance, is there sufficient evidence of a significant difference in the mean number of cars per day at the four locations?Using MS Excel,what is the computed value of the F statistic ? * Location II II IV 45 48 44 39 50 60 50 49 39 40 38 39 44 45 42 40 42 43 44 43 0.76 2.23 1.19 0.84
The following table displays descriptive statistics on the participants involved in a clinical trial that evaluates a new compound designed to improve wound healing in trauma patients. The new compound is compared against a placebo. Are any of the characteristics significantly different between groups? Characteristic New Compound Placebo p-value Mean age (years) 45.2 43.1 0.7564 Men (%) 45% 58% 0.215 Mean educational level (years) 12.1 13.2 0.6898 Mean annual income $36,560 $37,470 0.3546 Mean body mass index (BMI) 24.7 25.1 0.0051 Group of answer choices Mean age and Mean educational level Mean annual income Mean body mass index Mean body mass index and Mean age
(1) The following table summarizes the BMI collected for three different groups of a population. BMI N Mean SD Group A 100 21.6 2.1 Group B 100 24.8 1.8 Group C 100 27.9 1.3 Test the hypothesis whether there is a significant difference in the mean BMI scores among three groups. Use a = 0.05.
In 2022, Los Angles Times reported that the mean fare to fly from San Francisco to Los Angeles, on a discount ticket was around $360. A random sample of round-trip discount fares on this route last month is provided below: At the 0.05 significance level, can we conclude that the mean fare has increased? Amount 390 386 390 430 410 350 370 380 399 365 391 375 381 400 389 410 398 358 421 398
An analysis is conducted to compare mean time to pain relief (measured in minutes) under four competing treatment regimens. Summary statistics on the four treatments are shown below. Complete the following ANOVA Table. Source of Variation SS df MS F Between Groups Within Groups 3719.48 Total
Refer to the below table. Using an alpha = 0.05, test the claim that IQ scores are the same for children in three different blood lead level groups: low lead level, medium lead level, and high lead level). One-Way Analysis of Variance Summary Table for IQ Measurements for Children among Three Blood Lead Level Groups: Low Lead Level, Medium Lead Level, and High Lead Level. Source df SS MS F p Between-group (treatment) 2 469.1827 2677.864 2.30 0.104 Within-group (error) 118 203.6918 11745.05 Total 120
Show the 4-Step Method in testing significance of mean difference in the following case:A topic of recent clinical interest is the effect of different contraceptive methods on fertility. Suppose we wish to compare how long it takes users of either oral contraceptives (OCs) or diaphragms to become pregnant after stopping contraception. A study group of 20 OC users is formed, and diaphragm users who match each OC user with regard to age (within 5 years), race, parity (number of previous pregnancies), and socioeconomic status (SES) are found. The investigators compute the differences in time to fertility between previous OC and diaphragm users and find that the mean difference đ (OC minus diaphragm) in time to fertility is 4 months with a standard deviation (sd) of 8 months. Can we conclude that previous OC users take a significantly longer time to become pregnant than do previous diaphragm users?
atients suffering from rheumatic diseases or osteoporosis often suffer critical losses in bone mineral density (BMD). Alendronate is one medication prescribed to build or prevent further loss of BMD. Holcomb and Rothenberg (A-3) looked at 96 women taking alendronate to determine if a difference existed in the mean percent change in BMD among five different primary diagnosis classifications. Group 1 patients were diagnosed with rheumatoid arthritis (RA). Group 2 patients were a mixed collection of patients with diseases including lupus, Wegener’s granulomatosis and polyarteritis, and other vasculitic diseases (LUPUS). Group 3 patients had polymyalgia rheumatica or temporal arthritis (PMRTA). Group 4 patients had osteoarthritis (OA) and group 5 patients had osteoporosis (O) with no other rheumatic diseases identified in the medical record. Changes in BMD are shown in the following table. Discuss the Alendronate medication data in terms of variability. To determine if a difference…

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