Since the alternative hypothesis uses ≠, we will conduct a two-tailed test. Recall the standard normal probability table gives the area to the left of z test statistic called the p-value. An excerpt of this table is given below.z0.000.010.020.030.040.050.060.070.080.09−1.00.15870.15620.15390.15150.14920.14690.14460.14230.14010.1379−0.90.18410.18140.17880.17620.17360.17110.16850.16600.16350.1611−0.80.21190.20900.20610.20330.20050.19770.19490.19220.18940.1867Therefore, to find the p-value for this test, use the standard normal probability table to find the area to the left ofz = −0.91and multiply this value by 2, rounding the result to four decimal places.p-value = 2(area to the left of z = −0.91) = 2 =

The given value of test statistic is, z = -0.91 Using the z-table, the area to the left of z = -0.91…

Answered: ince the alternative hypothesis uses ≠,…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Since the alternative hypothesis uses ≠, we will conduct a two-tailed test. Recall the standard normal probability table gives the area to the left of z test statistic called the p-value. An excerpt of this table is given below.

z	0.00	0.01	0.02	0.03	0.04	0.05	0.06	0.07	0.08	0.09
−1.0	0.1587	0.1562	0.1539	0.1515	0.1492	0.1469	0.1446	0.1423	0.1401	0.1379
−0.9	0.1841	0.1814	0.1788	0.1762	0.1736	0.1711	0.1685	0.1660	0.1635	0.1611
−0.8	0.2119	0.2090	0.2061	0.2033	0.2005	0.1977	0.1949	0.1922	0.1894	0.1867

Therefore, to find the p-value for this test, use the standard normal probability table to find the area to the left of

z = −0.91

and multiply this value by 2, rounding the result to four decimal places.

p-value

2(area to the left of z = −0.91)

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