In Young's experiment the slit is illuminated by a light of wavelength 5900. A.U. if the sources are 1 mm apart, and screen is 1 m away from them, calculate the fringe width.
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- There is a 520 nm laser beam that is going through two narrow slits that creates a (interference) pattern at a wall that is 1.55 m from the slits. Calculate: a. Width of the central diffraction maximum on the wall is 4.27 cm. What is its angular width? (in radians) b. Use the radians calculated earlier to calculate the slit width in microns c. Distance of the 3rd diffraction minimum from the center of the patter on the wall d. Index numbers for difference orders where the interference maximum would be missing if the slit separation is 250µm e. If the slits remain at this width, what would the separate distance be if the 6th interference minimum overlapped with the 2nd diffraction minimumWhen violet light of wavelength 415 nm falls on a singleslit, it creates a central diffraction peak that is 8.20 cm wideon a screen that is 3.15 m away. How wide is the slit?Fringes in the Thomas Young experiment are produced using sodium light of wavelength 422 nm and two slits which are 1.1 mm apart. If the fringes are formed on a screen 0.8 m away from the slits, how far is the third order bright fringe from the middle of the screen? Give your answer in millimeters (mm).
- In a different young's experiment with 488nm light the second dark fringe is 1.2x10-3 (power of)m away from the center of the central bright fringe. The screen is 1.2m from the slits. What is the sepration of the slits?In a double split experiment, the slits were cut 1.9 cm apart and the screens are placed 8.81 m apart. What is the wavelength of the light that produceds a fourth order fringe on the screen 3.7 cm from the central fringe? Put answer in μm.A thin film of index nfilm 1.40 coats a thick glass plate of index n, = 1.50. glass The film is supposed to minimize reflection by interference from normally incident light (eincident = 0°) with wavelength 2 = 600nm. What is the minimum thickness, t, that the film can be made?
- o You illuminate a slit with a width of 79.9 µm with a light of wavelength 725 nm and observe the resulting diffraction pattern on a screen that is situated 2.75 m from the slit. What is the width w, in centimeters, of the pattern's o central maximum? W = cmIn a single-slit experiment, the slit width is 230 times the wavelength of the light. What is the width (in mmmm) of the central maximum on a screen 1.2 mm behind the slit?A laser light with wavelength of, 7 = 630nm, allowed to pass through double slit interference with a d= 0.03mm. The distance between the slits and the board is x=1.5 meter. What is the angle 01 of the first interference fringe in degrees?
- When performing a Young's double slit experiment, what is the required separation distance between the two slits (in micrometers) to cause 534 nm light to have its first order maximum at an angle of 22.1 degrees? Your Answer:A light source emits visible light of two wavelengths: λ = 400 nm and λ’ = 500 nm. The source is used ina double-slit interference experiment in which the length between the slits and the screen is L = 1.1 mand the spacing between the two slits is d = 1 mm.a) Find the separation distance between the third-order bright fringes for the twowavelengths. Do not use the small angle approximation. b)What if we examine the entire interference pattern due to the two wavelengths and lookfor overlapping fringes? Are there any locations on the screen where the bright fringes from the twowavelengths overlap exactly?Ex. 9: In Young's experiment interference bands are produced on the screen placed at 1.5 m from the two slits separated by a distance of 0.15 mm and illuminated by a light O of wavelength 4500 A, find (1) the fringe width and (2) the change in fringe width if screen is brought towards the slit by 50 cm.