Answered: Ex. 9: In Young's experiment… | bartleby

Related questions

Question

Ex. 9: In Young's experiment interference
bands are produced on the screen placed at
1.5 m from the two slits separated by a
distance of 0.15 mm and illuminated by a light
O
of wavelength 4500 A, find (1) the fringe
width and (2) the change in fringe width if
screen is brought towards the slit by 50 cm.

Expert Solution

Step by step

Solved in 2 steps

SEE SOLUTION Check out a sample Q&A here

Blurred answer

Similar questions

A hydrogen gas discharge lamp is used as a coherent light source illuminating NN slits in a barrier with a slit separation of 28 μmμm. The interference pattern is projected on a screen 2.00 m from the barrier. The first-order principal maxima to one side of the central maximum. The number of slits is sufficiently large that the individual lines are sharp and widely separated. Note that there are four different colors appearing in the source, violet is the color closest to the central maximum. λ=656λ=656 nm (red) λ=486λ=486 nm (cyan) λ=434λ=434 nm (blue-violet) λ=410λ=410 nm (violet) The blue-violet line is thin and somewhat faint, and it may be difficult to see without enlarging the figure. When viewing multiple orders of the interference pattern, the color sequence may change due to the interleaving of the different orders. 1. Using the values given in the problem statement, what is the distance along the screen, in centimeters, from the the central maximum to the first line? 2.…
In a Young’s double slit experiment, the screen is place 2.5 m from the slits, which have aseparation of 0.3 mm. If you shine a green laser with wavelength 500 nm on the slits, what isthe fringe separation between the central and first fringes?
Light of wavelength 588.2 nm illuminates a slit of width 0.63 mm. (a) At what distance from the slit should a screen be placed if the first minimum in the diffraction pattern is to be 0.86 mm from the central maximum? (b) Calculate the width of the central maximum. Step 1 (a) As shown in the figure, dark bands or minima occur where sin 0 = m(2/a). For the first minimum, m = 1 and the distance from the center of the central maximum to the first minimum is y₁ = L tan 8, where L is the distance of the viewing screen from the slit. 32 sin dark = 22/a 31 sin dark = λ/a HE 0 -1 sin dark = -λ/a -2 sin dark = -22/a Viewing screen a Because is very small, we can use the approximation tan sin 0 = m(2/a). Substituting the approximation and solving for the distance to the screen, we have 6.3 x 10 m ³ m ) (₁ L = = y ₁ ( ² ) = x 10-3 m x 10-⁹ m m.
X-rays with wavelength 0.02 nm are shown on a block of an unknown material. Effectively,the material acts like a Young’s double slit experiment, with the gap between atoms providingthe slit. If the separation between the central fringe and first bright fringe is 3.3 mm, and thematerial is 1.5 m from the screen, what is the distance between atoms in this material?
Problem 6: We use 633-nm light from a He-Ne laser to demonstrate Young's double-slit experiment. The interference pattern will be projected on a wall that is 5.0 m from the slits. We want the distance between the m=0 and m=1 maxima to be 25 cm. What slit separation is required to produce the desired interference pattern?
Ex. 56: In a biprism experiment interference bands are abserved at a distance of 1 m from the slit. A convex lens is put between the slit and eyepiece gives two images of slit 0.7 cm apart, the lens being 70 cm from eyepiece. Calculate the width of 100 bands, if light of wavelength 5890 A is used.
Small block is given an initial velocity measured along the horizontal floor of an elevator moving with a constant downward acceleration. Friction causes the block to move a distance S measured along the floor before it stopping. Experiment repeats with the same initial velocity (magnitude and direction) relative to the floor when the elevator has an upward acceleration of the same magnitude a, and the block slides a shorter distance s2. Determine the elevator acceleration a. Test your result for s = 1.3 m, s2 = 1 m, uk =0.5.Hint: The accelerations ax are not the same in the two experiments, only ay = a are the same.
In double-slit experiment using light of wavelength 600 nm, the angular width of a fringe formed on a distant screen is 0.1°. What is the spacing between the two slits?
Light with wavelength å passes through a narrow slit of width w and is seen on a screen which is located at a distance D in front of the slit. The first minimum of the diffraction pattern is at distanced from the middle of the central maximum. Calculate the wavelength of light if VAD. Give your D=1.3 m, d=1 mm and w = answer in nanometers.
Fringes in the Thomas Young experiment are produced using sodium light of wavelength 513 nm and two slits which are 1.2 mm apart. If the fringes are formed on a screen 1.1 m away from the slits, how far is the third order bright fringe from the middle of the screen? Give your answer in millimeters (mm)
What is the answer? with work?
In a single-slit diffraction experiment, a coherent light source illuminates a slit in a barrier, and the resulting pattern is projected on a screen that is separated from the barrier by a distance that is very large as compared to the slit width and the wavelength of the light source. A student makes sketches of the resulting patterns. While the center of each bright or dark band is accurately represented, the shading is qualitative, and the choice of color may not reflect the wavelength of the light source. The distance from the barrier to the screen is 2.65m, and the slit has a width of 7.7μm.

SEE MORE QUESTIONS