Need help with stats question In trying to determine the skawness of the data set3.1 4.3 5.7 2.8 6.9 23 11.0 9.5 87 3.1 3.4 42 29 28 112we can conclude thatOa The mean is greater than the median hence the data is approximately symmetricOb. We do not have enough information to determine skewnessOc The mean is greater than the median hence the data is skewed left.O d. The mean is greater than the median hence the data is skewed right

When the tail of the distribution is elongated to the right side, the shape of the distribution is positively or right skewed. When the tail of the distribution is elongated to the left side, the shape of the distribution is negatively or left skewed. When the tails of the distribution are elongated uniformly to the both sides, the shape of the distribution is uniformly distributed. In this case, the tails of the distribution are elongated uniformly to the both sides. Hence, the shape of the distribution is symmetric. It is known that, for positively skewed distribution mean is greater than median. That is, Mean > Median. It is known that, for negatively skewed distribution mean is lesser than median. That is, Mean < Median It is known that, for symmetric distribution mean is same the median. That is, Mean = Median.Mean: Mean is the expected value of a set of observations. In other words, mean is he average of the observations. The total number of observations is n = 15. The mean for the data is obtained as, Mean = (3.1 + 4.3 + 5.7 + 2.8 + 6.9 + 2.3 + 11 + 9.5 + 8.7 + 3.1 + 3.4 + 4.2 + 2.9 + 2.8 + 11.2)/15 = 81.9/15 = 5.46. Thus, the mean is 5.46. Median: Median is the middle most value of a set of observations. Arrange the data in ascending order. That is, 2.3, 2.8, 2.8, 2.9, 3.1, 3.1, 3.4, 4.2, 4.3, 5.7, 6.9, 8.7, 9.5, 11, and 11.2. There is n = 15 observations. Hence, the median will be the [(n + 1)/2]th = [(15 + 1)/2]th = 8th observation. Thus, the 8th observation is 4.2. Thus, the median is 4.2. Here, the mean is greater than the median. Hence, the data is skewed right. Correct option is d.