In this statics problem I am given a triangular distributed load on a cable. Attached is the given info for the problem. I know the basic steps to complete the problem but I am having issues figuring out where the triangular distributed load and 15 degrees given work into the problem. I’ve tried finding the Moment around B with the distributed load and then the two components of Tension at A (using sin(15) and cos(15) respectively but this did not work.
In this statics problem I am given a triangular distributed load on a cable. Attached is the given info for the problem. I know the basic steps to complete the problem but I am having issues figuring out where the triangular distributed load and 15 degrees given work into the problem. I’ve tried finding the Moment around B with the distributed load and then the two components of Tension at A (using sin(15) and cos(15) respectively but this did not work.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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In this statics problem I am given a triangular distributed load on a cable. Attached is the given info for the problem. I know the basic steps to complete the problem but I am having issues figuring out where the triangular distributed load and 15 degrees given work into the problem. I’ve tried finding the Moment around B with the distributed load and then the two components of Tension at A (using sin(15) and cos(15) respectively but this did not work.
![Pre blem
Given:
4
A
F
7.111
20
B
AT
-X
WX
3(ycs+x sinis)
20¹
w=540 lb/ft
Findi Tmax
Solution:
(+ Mg = 0 = (wx) ( x) - To'y 'cas15 = To`xsin 15 Toxg
Tryces 15 + xsin 15)= 3
3 36
2939.39 16
To=
То
T[20] =√(2134,39)² + (540-20)² = 11.2 kips
WX](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F273828c8-6b82-4a3c-870a-2dcccf003166%2Fdd2d3dcc-4506-40ea-8662-0fe729c6e93b%2Fvk9t3t_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Pre blem
Given:
4
A
F
7.111
20
B
AT
-X
WX
3(ycs+x sinis)
20¹
w=540 lb/ft
Findi Tmax
Solution:
(+ Mg = 0 = (wx) ( x) - To'y 'cas15 = To`xsin 15 Toxg
Tryces 15 + xsin 15)= 3
3 36
2939.39 16
To=
То
T[20] =√(2134,39)² + (540-20)² = 11.2 kips
WX
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