In this section of the experiment, we will locate a smooth surface at an angle and measure the distance between the starting and finishing points of the hill. Then we'll place a ball at the top of the hill, let it go, and time how long it takes for the ball to roll down the hill, and repeat until we get 5 measurements total. O8 +C.6+ 0.7y +0-46 +0. 6G - 0.652 sec

College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Experiment #2
In this section of the experiment, we will locate a smooth surface at an angle and measure the distance
between the starting and finishing points of the hill. Then we'll place a ball at the top of the hill, let it go,
and time how long it takes for the ball to roll down the hill, and repeat until we get 5 measurements total.
O.8+C.6+ 0.74 +0-46 +0. 6G
- 0.652 sec
t -
2ain
S= 67in = 1.7018m
Sine: 0.4328
AB - 29in
g sino t?
AC = 67in
(2) (67) (2)
o.4328(0.652)²
29
AB
Sino -
AC
= 0.4328
67
g= 18.5m/s*
O- sin'(0.4328)
e -25.6°
18.5
9.8
Jo
Ni nomal renct
= 1. ४r।
= 88.7'1.
88.71timos the orginal acceleration
due to grauity.
wigsino = r a
a = g sine
when using midde valve; t = 0.74sec
2s
(2)(67) ( 2
= 14.36| m/p2
Sin e t?
0.4328( 0.74) 2
Time of toy going doun hill:
Trial Time (Sec)
14.361 - 1,U65 =146.51,
go
0.80 sec
0.60 sec
0.74 sec
9.80
3
96.5%. times the orginal accelevation due togravity
4
0.46sec
O. 66 Sec
Kinematicequation
Given
a:g sino
S > U+ +fat
S=gsinot?
Sinetz
Transcribed Image Text:Experiment #2 In this section of the experiment, we will locate a smooth surface at an angle and measure the distance between the starting and finishing points of the hill. Then we'll place a ball at the top of the hill, let it go, and time how long it takes for the ball to roll down the hill, and repeat until we get 5 measurements total. O.8+C.6+ 0.74 +0-46 +0. 6G - 0.652 sec t - 2ain S= 67in = 1.7018m Sine: 0.4328 AB - 29in g sino t? AC = 67in (2) (67) (2) o.4328(0.652)² 29 AB Sino - AC = 0.4328 67 g= 18.5m/s* O- sin'(0.4328) e -25.6° 18.5 9.8 Jo Ni nomal renct = 1. ४r। = 88.7'1. 88.71timos the orginal acceleration due to grauity. wigsino = r a a = g sine when using midde valve; t = 0.74sec 2s (2)(67) ( 2 = 14.36| m/p2 Sin e t? 0.4328( 0.74) 2 Time of toy going doun hill: Trial Time (Sec) 14.361 - 1,U65 =146.51, go 0.80 sec 0.60 sec 0.74 sec 9.80 3 96.5%. times the orginal accelevation due togravity 4 0.46sec O. 66 Sec Kinematicequation Given a:g sino S > U+ +fat S=gsinot? Sinetz
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