In this reduction of aldehyde to carboxylic acids using sodium chlorite, where did the C = O- - H come from ? (highlighted in green), I checked the wiki and it said it came from HCIO2, and oxygen from C = O took the H from HCIO2. Now the question is, how did the HCIO2 formed from the reaction conditions shown above? Did the buffer provide the hydrogen to the ClO2- anion? Oxidation of Carbonyl Compounds aldehydes to carboxylic acids 3 sodium chlorite NaCIO₂ aq. Na₂HPO4 (buffer) C H (+ 2

In this reduction of aldehyde to carboxylic acids using sodium chlorite, where did the C = O- - H come from ? (highlighted in green), I checked the wiki and it said it came from HCIO2, and oxygen from C = O took the H from HCIO2. Now the question is, how did the HCIO2 formed from the reaction conditions shown above? Did the buffer provide the hydrogen to the ClO2- anion? Oxidation of Carbonyl Compounds aldehydes to carboxylic acids 3 sodium chlorite NaCIO₂ aq. Na₂HPO4 (buffer) C H (+ 2

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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