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In this question, I don't understand the highlight why it get 10.5 since the question is only 10? Please help me to explain it.

In this question, I don't understand the highlight why it get 10.5 since the question is only 10? Please help me to explain it.

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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In this question, I don't understand the highlight why it get 10.5 since the question is only 10? Please help me to explain it. Thank you!

25+Test... X 2018-11-13+Test2... X Lecture+9+Notes... X Lecture+10+Notes... X Lecture+11+Notes... X Lecture+7+Notes... X Lecture+8+Notes... 2019-06-19+T... U. T A factory which produces chips in lots of ten thousand uses the following scheme to check the quality of its product. From each lot of chips produced, a random sample of size 500 chips is taken. If the sample contains 10 or less defectives, the lot is passed. If the sample contains more than 10 defectives, another random sample of size 500 is chosen from the lot. If this sample contains 10 or less defectives, the lot is passed. Otherwise the lot is rejected. If a lot actually contains 5% defectives, find the probability that it will pass. Solution: Given that the percent of defectives in the lot is p=0.05. In a random sample of 500, the probability of getting 10 or less defectives is 500 500 500 (0.0s)" (0.95)*90 + (0.0s) (0.95)*91 o.os) (0.95)00 ...+ 10 9 which can be approximated using the normal distribution. H = np = 500(0.05)= 25, o² = npq = 500(0.05)(0.95) = 23.75 . X - u 10.5 – 25 Hence P(X <10.5)= P = P(Z <-2.975)= 0.0014 V23.75 The lot will pass if a random sample of 500 contains 10 or less defectives, or (1) (2) the sample in (1) contains more than 10 defectives, and another random sample of 500 contains 10 or less defectives P(lot will pass)= 0.0014 + (1-0.0014)(0.0014) = 0.002798 1 Previous Next Dashboard Calendar Тo Do Notifications Inbox 000
Transcribed Image Text:25+Test... X 2018-11-13+Test2... X Lecture+9+Notes... X Lecture+10+Notes... X Lecture+11+Notes... X Lecture+7+Notes... X Lecture+8+Notes... 2019-06-19+T... U. T A factory which produces chips in lots of ten thousand uses the following scheme to check the quality of its product. From each lot of chips produced, a random sample of size 500 chips is taken. If the sample contains 10 or less defectives, the lot is passed. If the sample contains more than 10 defectives, another random sample of size 500 is chosen from the lot. If this sample contains 10 or less defectives, the lot is passed. Otherwise the lot is rejected. If a lot actually contains 5% defectives, find the probability that it will pass. Solution: Given that the percent of defectives in the lot is p=0.05. In a random sample of 500, the probability of getting 10 or less defectives is 500 500 500 (0.0s)" (0.95)*90 + (0.0s) (0.95)*91 o.os) (0.95)00 ...+ 10 9 which can be approximated using the normal distribution. H = np = 500(0.05)= 25, o² = npq = 500(0.05)(0.95) = 23.75 . X - u 10.5 – 25 Hence P(X <10.5)= P = P(Z <-2.975)= 0.0014 V23.75 The lot will pass if a random sample of 500 contains 10 or less defectives, or (1) (2) the sample in (1) contains more than 10 defectives, and another random sample of 500 contains 10 or less defectives P(lot will pass)= 0.0014 + (1-0.0014)(0.0014) = 0.002798 1 Previous Next Dashboard Calendar Тo Do Notifications Inbox 000
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