In this problem you will solve the initial value problem 39x?y" – 122ry + 66y = 0, y(1) = 0, y (1) = 9. (1) The largest intervals that may be considered for the domain of the solution to 39x²y" – 122xy + 66y = 0 are either or For -00 type -inf and for oo type inf. (2) Let C, and C, be arbitrary constants. The general solution to the homogeneous differential equation 39x?y" – 122ry + 66y = 0 is the function y(r) = C1 4 (x) + C2 Y2(T) = C1 +C2 (3) The unique solution to the initial value problem 39x?y" – 122ay + 66y = 0, y(1) = 0, y (1) = 9. is the function y(x) for æ E
In this problem you will solve the initial value problem 39x?y" – 122ry + 66y = 0, y(1) = 0, y (1) = 9. (1) The largest intervals that may be considered for the domain of the solution to 39x²y" – 122xy + 66y = 0 are either or For -00 type -inf and for oo type inf. (2) Let C, and C, be arbitrary constants. The general solution to the homogeneous differential equation 39x?y" – 122ry + 66y = 0 is the function y(r) = C1 4 (x) + C2 Y2(T) = C1 +C2 (3) The unique solution to the initial value problem 39x?y" – 122ay + 66y = 0, y(1) = 0, y (1) = 9. is the function y(x) for æ E
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Transcribed Image Text:In this problem you will solve the initial value problem
39x y" – 122ry + 66y = 0, y(1) = 0, y (1) = 9.
(1) The largest intervals that may be considered for the domain of the solution to 39x?y" – 122ry + 66y = 0 are either
or
For -0o type -inf and for o type inf.
(2) Let C, and C, be arbitrary constants. The general solution to the homogeneous differential equation 39x?y" - 122ry + 66y = 0 is the
function y(z) = C1 4 (2) + C2 y>(x) = C1
+C2
(3) The unique solution to the initial value problem
39x?y" - 122ay+ 66y
= 0, y(1) = 0, y (1) = 9.
is the function y(x):
for x E
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