In this problem consider the object a 2 dimensional square in 2 dimensional space so all field lines are seen, and Gauss's Law holds true in this 2 dimensional space. It is given that the red charge has a magnitude of 4.8 nC, the distance between the charges is 5.0 cm, each side of the square is 10 cm and the mid point between the two charges is at the center of the square. From the figure we can conclude the following. The electric charge of the blue charge is nC. The total or net flux through the entire square is Nm/c The flux through the left side of the square is Nm/C The flux through the top side of the square is Nm?/C The flux through the right side of the square is Nm?/C The flux through the bottom side of the square is Nm2/C
In this problem consider the object a 2 dimensional square in 2 dimensional space so all field lines are seen, and Gauss's Law holds true in this 2 dimensional space. It is given that the red charge has a magnitude of 4.8 nC, the distance between the charges is 5.0 cm, each side of the square is 10 cm and the mid point between the two charges is at the center of the square. From the figure we can conclude the following. The electric charge of the blue charge is nC. The total or net flux through the entire square is Nm/c The flux through the left side of the square is Nm/C The flux through the top side of the square is Nm?/C The flux through the right side of the square is Nm?/C The flux through the bottom side of the square is Nm2/C
Physics for Scientists and Engineers with Modern Physics
10th Edition
ISBN:9781337553292
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter24: Electric Potential
Section: Chapter Questions
Problem 45AP: A solid, insulating sphere of radius a has a uniform charge density throughout its volume and a...
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![In this problem consider the object a 2 dimensional square in 2 dimensional space so all field lines are seen, and Gauss's Law holds true in this 2 dimensional space. It is given that the red charge has a magnitude of 4.8 nC, the distance between the charges is 5.0 cm,
each side of the square is 10 cm and the mid point between the two charges is at the center of the square.
From the figure we can conclude the following.
The electric charge of the blue charge is
nC.
The total or net flux through the entire square is
Nm?/C
The flux through the left side of the square is
Nm2/C
The flux through the top side of the square is
Nm/C
The flux through the right side of the square is
Nm2/C
The flux through the bottom side of the square is
Nm2/C](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F88fd920b-5877-4160-aaa2-6103f24e0e72%2F28466665-564c-4972-b17d-320dd3b80aa9%2F5ymmp4l_processed.png&w=3840&q=75)
Transcribed Image Text:In this problem consider the object a 2 dimensional square in 2 dimensional space so all field lines are seen, and Gauss's Law holds true in this 2 dimensional space. It is given that the red charge has a magnitude of 4.8 nC, the distance between the charges is 5.0 cm,
each side of the square is 10 cm and the mid point between the two charges is at the center of the square.
From the figure we can conclude the following.
The electric charge of the blue charge is
nC.
The total or net flux through the entire square is
Nm?/C
The flux through the left side of the square is
Nm2/C
The flux through the top side of the square is
Nm/C
The flux through the right side of the square is
Nm2/C
The flux through the bottom side of the square is
Nm2/C
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