In this balanced chemical equation, 2Co(NO3)3 + 3(NH4)2S - ----> Co2S3 + 6 NH¼NO3, how many atoms of N (total) are on the reactant side of the equation? А. 6 В. 4 C. 8 D. 10 E. 12
In this balanced chemical equation, 2Co(NO3)3 + 3(NH4)2S - ----> Co2S3 + 6 NH¼NO3, how many atoms of N (total) are on the reactant side of the equation? А. 6 В. 4 C. 8 D. 10 E. 12
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![### Question
In this balanced chemical equation, 2Co(NO₃)₃ + 3(NH₄)₂S ---> Co₂S₃ + 6 NH₄NO₃, how many atoms of N (total) are on the reactant side of the equation?
- ○ A. 6
- ○ B. 4
- ○ C. 8
- ○ D. 10
- ○ E. 12
### Explanation
To determine the total number of nitrogen atoms on the reactant side:
1. **Co(NO₃)₃**: There are 2 molecules of Co(NO₃)₃, and each contains 3 nitrogen atoms:
\(2 \times 3 = 6 \) nitrogen atoms.
2. **(NH₄)₂S**: There are 3 molecules of (NH₄)₂S, and each contains 2 nitrogen atoms:
\(3 \times 2 = 6 \) nitrogen atoms.
Add the nitrogen atoms from both compounds:
\(6 + 6 = 12\) nitrogen atoms
The correct answer is **E. 12**.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F3c6fee6f-4c42-45ae-a179-2e46b70b7779%2F18fd4450-82aa-4c7d-9cdd-15a642e5af4b%2Fi4tfjp_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Question
In this balanced chemical equation, 2Co(NO₃)₃ + 3(NH₄)₂S ---> Co₂S₃ + 6 NH₄NO₃, how many atoms of N (total) are on the reactant side of the equation?
- ○ A. 6
- ○ B. 4
- ○ C. 8
- ○ D. 10
- ○ E. 12
### Explanation
To determine the total number of nitrogen atoms on the reactant side:
1. **Co(NO₃)₃**: There are 2 molecules of Co(NO₃)₃, and each contains 3 nitrogen atoms:
\(2 \times 3 = 6 \) nitrogen atoms.
2. **(NH₄)₂S**: There are 3 molecules of (NH₄)₂S, and each contains 2 nitrogen atoms:
\(3 \times 2 = 6 \) nitrogen atoms.
Add the nitrogen atoms from both compounds:
\(6 + 6 = 12\) nitrogen atoms
The correct answer is **E. 12**.
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