In this balanced chemical equation, 2Co(NO3)3 + 3(NH4)2S - ----> Co2S3 + 6 NH¼NO3, how many atoms of N (total) are on the reactant side of the equation? А. 6 В. 4 C. 8 D. 10 E. 12

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### Question

In this balanced chemical equation, 2Co(NO₃)₃ + 3(NH₄)₂S ---> Co₂S₃ + 6 NH₄NO₃, how many atoms of N (total) are on the reactant side of the equation?

- ○ A. 6
- ○ B. 4
- ○ C. 8
- ○ D. 10
- ○ E. 12

### Explanation

To determine the total number of nitrogen atoms on the reactant side:

1. **Co(NO₃)₃**: There are 2 molecules of Co(NO₃)₃, and each contains 3 nitrogen atoms:  
    \(2 \times 3 = 6 \) nitrogen atoms.

2. **(NH₄)₂S**: There are 3 molecules of (NH₄)₂S, and each contains 2 nitrogen atoms:  
    \(3 \times 2 = 6 \) nitrogen atoms.

Add the nitrogen atoms from both compounds:
\(6 + 6 = 12\) nitrogen atoms

The correct answer is **E. 12**.
Transcribed Image Text:### Question In this balanced chemical equation, 2Co(NO₃)₃ + 3(NH₄)₂S ---> Co₂S₃ + 6 NH₄NO₃, how many atoms of N (total) are on the reactant side of the equation? - ○ A. 6 - ○ B. 4 - ○ C. 8 - ○ D. 10 - ○ E. 12 ### Explanation To determine the total number of nitrogen atoms on the reactant side: 1. **Co(NO₃)₃**: There are 2 molecules of Co(NO₃)₃, and each contains 3 nitrogen atoms: \(2 \times 3 = 6 \) nitrogen atoms. 2. **(NH₄)₂S**: There are 3 molecules of (NH₄)₂S, and each contains 2 nitrogen atoms: \(3 \times 2 = 6 \) nitrogen atoms. Add the nitrogen atoms from both compounds: \(6 + 6 = 12\) nitrogen atoms The correct answer is **E. 12**.
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