In the system shown in Fig. 3-17(a), force F accelerates block m₁ to the right. Find its acceleration in terms of F and the coefficient of friction at the contact surfaces. 15 m₂ m₂ F
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- Do 3-7, 3-8 and 3-11 -√3.7 # 3-7 Determine the magnitude and direction angle of force F, so that the particle shown in Fig. P3-7 is in equilib- rium. F3 = 10 kip 26° 1F₂=4 kip Fig. P3-7 26° F₂ F₁ = 2 kipA monkey pushes a box of mass 25 kg in a straight line across a rough floor. The applied force F has magnitude 85 N and acts downward at an angle 0 = 10° with respect to the horizontal, as shown below. The box is initially at rest at the position x/ a). Find the coefficient of friction between the box and the floor. and it has speed v2 = 0.55 m/s at position x2 = 3.50 m. 0 m, b). What is the net work done? c). How much work (magnitude and sign) is done by the friction force? m Hint: this q involves constant acceleration, Newton's laws, workUnder the action of force P, the constant acceleration of block B is 6.4 ft/sec² up the incline. For the instant when the velocity of B is 2.6 ft/sec up the incline, determine the velocity of B relative to A (positive if up the slope, negative if down), the acceleration of B relative to A (positive if up the slope, negative if down), and the absolute velocity of point C (positive if up the slope, negative if down) of the cable. Answers: VB/A = AB/A Vc = = 15° i i B ft/sec ft/sec² ft/sec