Under the action of force P, the constant acceleration of block B is 6.4 ft/sec² up the incline. For the instant when the velocity of B is 2.6 t/sec up the incline, determine the velocity of B relative to A (positive if up the slope, negative if down), the acceleration of B relative to A (positive if up the slope, negative if down), and the absolute velocity of point C (positive if up the slope, negative if down) of the cable. Answers: 15° B

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Under the action of force P, the constant acceleration of block B is 6.4 ft/sec² up the incline. For the instant when the velocity of B is 2.6
ft/sec up the incline, determine the velocity of B relative to A (positive if up the slope, negative if down), the acceleration of B relative to
A (positive if up the slope, negative if down), and the absolute velocity of point C (positive if up the slope, negative if down) of the cable.
Answers:
VB/A =
AB/A
Vc =
=
15°
i
i
B
ft/sec
ft/sec²
ft/sec
Transcribed Image Text:Under the action of force P, the constant acceleration of block B is 6.4 ft/sec² up the incline. For the instant when the velocity of B is 2.6 ft/sec up the incline, determine the velocity of B relative to A (positive if up the slope, negative if down), the acceleration of B relative to A (positive if up the slope, negative if down), and the absolute velocity of point C (positive if up the slope, negative if down) of the cable. Answers: VB/A = AB/A Vc = = 15° i i B ft/sec ft/sec² ft/sec
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