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Learning Goal: To understand the dynamics of a series R-C circuit Consider a series circuit containing a resistor of resistance R and a capacitor of capacitance C connected to a source of EMF E with negligible internal resistance. The wires are also assumed to have zero resistance. Initially, the switch is open and the capacitor discharged. (Eigure 1) Let us try to understand the processes that take place after the switch is closed. The charge of the capacitor, the current in the circuit, and, correspondingly, the voltages across the resistor and the capacitor will be changing. Note that at any moment in time during the life of our circuit, Kirchhoff's loop rule holds and, indeed, it is helpful: E-VR-Vc=0, where VR is the voltage across the resistor and Vc is the voltage across the capacitor. Figure R 4-0 • C=90=0 < 1 of 1 Part B Immediately after the switch is closed, what is the voltage across the resistor? O E 018 O zero Submit Request Answer Part C Immediately after the switch is closed, what is the direction of the current in the circuit? O clockwise O counterclockwise O There is no current because the capacitor does not allow the current to pass through. Submit Request Answer Part D Complete previous part(s) Part E Eventually, the process approaches a steady state. In that steady state, the charge of the capacitor is not changing. What is the current in the circuit in the steady state? ▸ View Available Hint(s) E R+C O REC O CER Ozero 1

Learning Goal: To understand the dynamics of a series R-C circuit Consider a series circuit containing a resistor of resistance R and a capacitor of capacitance C connected to a source of EMF E with negligible internal resistance. The wires are also assumed to have zero resistance. Initially, the switch is open and the capacitor discharged. (Eigure 1) Let us try to understand the processes that take place after the switch is closed. The charge of the capacitor, the current in the circuit, and, correspondingly, the voltages across the resistor and the capacitor will be changing. Note that at any moment in time during the life of our circuit, Kirchhoff's loop rule holds and, indeed, it is helpful: E-VR-Vc=0, where VR is the voltage across the resistor and Vc is the voltage across the capacitor. Figure R 4-0 • C=90=0 < 1 of 1 Part B Immediately after the switch is closed, what is the voltage across the resistor? O E 018 O zero Submit Request Answer Part C Immediately after the switch is closed, what is the direction of the current in the circuit? O clockwise O counterclockwise O There is no current because the capacitor does not allow the current to pass through. Submit Request Answer Part D Complete previous part(s) Part E Eventually, the process approaches a steady state. In that steady state, the charge of the capacitor is not changing. What is the current in the circuit in the steady state? ▸ View Available Hint(s) E R+C O REC O CER Ozero 1

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
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Item 10 Learning Goal: To understand the dynamics of a series R-C circuit. Consider a series circuit containing a resistor of resistance R and a capacitor of capacitance C connected to a source of EMF & with negligible internal resistance. The wires are also assumed to have zero resistance. Initially, the switch is open and the capacitor discharged. (Figure 1) Let us try to understand the processes that take place after the switch is closed. The charge of the capacitor, the current in the circuit, and, correspondingly, the voltages across the resistor and the capacitor will be changing. Note that at any moment in time during the life of our circuit, Kirchhoff's loop rule holds and, indeed, it is helpful: E-VR-Vc = 0, where VR is the voltage across the resistor and Vc is the voltage across the capacitor. Figure & R ww io=0 C 90=0 1 of 1 Part B Immediately after the switch is closed, what is the voltage across the resistor? Submit Request Answer E Part C zero Immediately after the switch is closed, what is the direction of the current in the circuit? O clockwise Submit O counterclockwise O There is no current because the capacitor does not allow the current to pass through. Part D Complete previous part(s) Part E Eventually, the process approaches a steady state. In that steady state, the charge of the capacitor is not changing. What is the current in the circuit in the steady state? ► View Available Hint(s) R E R+C E R-C Request Answer E C-R zero 10 of 15 Review
Transcribed Image Text:Item 10 Learning Goal: To understand the dynamics of a series R-C circuit. Consider a series circuit containing a resistor of resistance R and a capacitor of capacitance C connected to a source of EMF & with negligible internal resistance. The wires are also assumed to have zero resistance. Initially, the switch is open and the capacitor discharged. (Figure 1) Let us try to understand the processes that take place after the switch is closed. The charge of the capacitor, the current in the circuit, and, correspondingly, the voltages across the resistor and the capacitor will be changing. Note that at any moment in time during the life of our circuit, Kirchhoff's loop rule holds and, indeed, it is helpful: E-VR-Vc = 0, where VR is the voltage across the resistor and Vc is the voltage across the capacitor. Figure & R ww io=0 C 90=0 1 of 1 Part B Immediately after the switch is closed, what is the voltage across the resistor? Submit Request Answer E Part C zero Immediately after the switch is closed, what is the direction of the current in the circuit? O clockwise Submit O counterclockwise O There is no current because the capacitor does not allow the current to pass through. Part D Complete previous part(s) Part E Eventually, the process approaches a steady state. In that steady state, the charge of the capacitor is not changing. What is the current in the circuit in the steady state? ► View Available Hint(s) R E R+C E R-C Request Answer E C-R zero 10 of 15 Review
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mics of a series R-C circuit. I containing a resistor of resistance R and a e C connected to a source of EMF & with ance. The wires are also assumed to have the switch is open and the capacitor the processes that take place after the marge of the capacitor, the current in the ingly, the voltages across the resistor and anging. Note that at any moment in time cuit, Kirchhoff's loop rule holds and, indeed, Vc = 0, where VR is the voltage across the voltage across the capacitor. R ww io=0 C = 40=0 1 of 1 Part F In the steady state, what is the charge q of the capacitor? Express your answer in terms of any or all of E, R, and C. ► View Available Hint(s) VE ΑΣΦ 9= Submit Part G W = How much work W is done by the voltage source by the time the steady state is reached? Express your answer in terms of any or all of E, R, and C. ► View Available Hint(s) Submit Provide Feedback C V ΑΣΦ ? LATI ?
Transcribed Image Text:mics of a series R-C circuit. I containing a resistor of resistance R and a e C connected to a source of EMF & with ance. The wires are also assumed to have the switch is open and the capacitor the processes that take place after the marge of the capacitor, the current in the ingly, the voltages across the resistor and anging. Note that at any moment in time cuit, Kirchhoff's loop rule holds and, indeed, Vc = 0, where VR is the voltage across the voltage across the capacitor. R ww io=0 C = 40=0 1 of 1 Part F In the steady state, what is the charge q of the capacitor? Express your answer in terms of any or all of E, R, and C. ► View Available Hint(s) VE ΑΣΦ 9= Submit Part G W = How much work W is done by the voltage source by the time the steady state is reached? Express your answer in terms of any or all of E, R, and C. ► View Available Hint(s) Submit Provide Feedback C V ΑΣΦ ? LATI ?
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