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ww R₁ 5.0 Ω a R₂ 78 02 1₁ E₁24.0 V 1² 0.100 Loopa 60V T3 Four 13, E3 AROV Loop 1 48.0 k 1₂ 0.50 Ω LOOP 3 i 0.05 22 h R₂ ww 40 Ω R₁ - 20 Ω e T4 0.20 $2 g E4 = 36.0 V

ww R₁ 5.0 Ω a R₂ 78 02 1₁ E₁24.0 V 1² 0.100 Loopa 60V T3 Four 13, E3 AROV Loop 1 48.0 k 1₂ 0.50 Ω LOOP 3 i 0.05 22 h R₂ ww 40 Ω R₁ - 20 Ω e T4 0.20 $2 g E4 = 36.0 V

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I need help on getting an easier understanding of using Kirchhoff's Current Loop rules.

KIRCHHOFF’S RULES

  • Kirchhoff’s first rule—the junction rule. The sum of all currents entering a junction must equal the sum of all currents leaving the junction.
  • Kirchhoff’s second rule—the loop rule. The algebraic sum of changes in potential around any closed circuit path (loop) must be zero.

Analyze the following multi-voltage source circuit for all currents. Use the current directions and loop notation as shown on the figure attached.

 

  • The value of current I1 = ______ A
  • The value of current I2 = ______ A
  • The value of current I3 = ______ A
  • What is the total power dissipated in all the internal resistances (r1, r2, r3, r4), in milliWatts?
ww R₁ 5.0 Ω a R₂ 78 02 1₁ E₁24.0 V 1² 0.100 Loopa 60V T3 Four 13, E3 AROV Loop 1 48.0 k 1₂ 0.50 Ω LOOP 3 i 0.05 22 h R₂ ww 40 Ω R₁ - 20 Ω e T4 0.20 $2 g E4 = 36.0 V
Transcribed Image Text:ww R₁ 5.0 Ω a R₂ 78 02 1₁ E₁24.0 V 1² 0.100 Loopa 60V T3 Four 13, E3 AROV Loop 1 48.0 k 1₂ 0.50 Ω LOOP 3 i 0.05 22 h R₂ ww 40 Ω R₁ - 20 Ω e T4 0.20 $2 g E4 = 36.0 V
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