In the previous problem, we investigated Kimberly-Clark Corporation's assertion that the company should put 60 tissues in a cold-care box of Kleenex tissues. Another approach to the problem is to consider the proportion of Kleenex users who use fewer than 60 tissues when they have a cold. Now the population parameter of interest is p, the proportion of all Kleenex users who use fewer than 60 tissues when they have a cold. Kimberly-Clark Corporation's belief that the company should put 60 tissues in a cold-care box will be supported if the median number of tissues used is 60. Now, if the true median is, in fact, 60, then half of the Kleenex users will use less than 60 tissues (i.e., p = 0.5). Is there evidence to indicate that the population proportion differs from 0.5? We will select a = 0.05 as the level of signicance for the test. Recall that the survey results for the 250 sampled Kleenex users are stored in the tissues.txt data file. In addition to the number of tissues used by each person, the file contains a qualitative variable - called USED60 - representing whether the person used fewer or more than 60 tissues. (The values of USED60 in the data set are BELOW=0 or ABOVE=1.) The appropriate null and alternative hypotheses, Ho and Ha, for pare O Ho: p=0.5 vs Ha: p > 0.5 O Ho: p=0.5 vs Ha: p = 0.5 O Ho: p=0.5 vs Ha: p < 0.5

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Data: https://www.dropbox.com/s/3l1jouhkep9c3jr/tissues.txt?dl=0

In the previous problem, we investigated Kimberly-Clark Corporation's assertion that the company should put
60 tissues in a cold-care box of Kleenex tissues. Another approach to the problem is to consider the
proportion of Kleenex users who use fewer than 60 tissues when they have a cold. Now the population
parameter of interest is p, the proportion of all Kleenex users who use fewer than 60 tissues when they have a
cold.
Kimberly-Clark Corporation's belief that the company should put 60 tissues in a cold-care box will be
supported if the median number of tissues used is 60. Now, if the true median is, in fact, 60, then half of the
Kleenex users will use less than 60 tissues (i.e., p = 0.5). Is there evidence to indicate that the population
proportion differs from 0.5? We will select a = 0.05 as the level of signicance for the test.
Recall that the survey results for the 250 sampled Kleenex users are stored in the tissues.txt data file.
In addition to the number of tissues used by each person, the file contains a qualitative variable - called
USED60 - representing whether the person used fewer or more than 60 tissues. (The values of USED60 in the
data set are BELOW=0 or ABOVE=1.)
The appropriate null and alternative hypotheses, Ho and Ha, for pare
O Ho: p= 0.5 vs H₁ : p > 0.5
O Ho p = 0.5 vs Ha: p = 0.5
O Ho: p= 0.5 vs Ha: p < 0.5
Transcribed Image Text:In the previous problem, we investigated Kimberly-Clark Corporation's assertion that the company should put 60 tissues in a cold-care box of Kleenex tissues. Another approach to the problem is to consider the proportion of Kleenex users who use fewer than 60 tissues when they have a cold. Now the population parameter of interest is p, the proportion of all Kleenex users who use fewer than 60 tissues when they have a cold. Kimberly-Clark Corporation's belief that the company should put 60 tissues in a cold-care box will be supported if the median number of tissues used is 60. Now, if the true median is, in fact, 60, then half of the Kleenex users will use less than 60 tissues (i.e., p = 0.5). Is there evidence to indicate that the population proportion differs from 0.5? We will select a = 0.05 as the level of signicance for the test. Recall that the survey results for the 250 sampled Kleenex users are stored in the tissues.txt data file. In addition to the number of tissues used by each person, the file contains a qualitative variable - called USED60 - representing whether the person used fewer or more than 60 tissues. (The values of USED60 in the data set are BELOW=0 or ABOVE=1.) The appropriate null and alternative hypotheses, Ho and Ha, for pare O Ho: p= 0.5 vs H₁ : p > 0.5 O Ho p = 0.5 vs Ha: p = 0.5 O Ho: p= 0.5 vs Ha: p < 0.5
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