In the power and energy experiment, the power (PRL) dissipated across the load resistor R is given by the equation: P =g?_R2 (R+R¿)? 280 260 y = 102010x - 1E-12 240 R2 = 1 220 200 180 160 140 ........ .... 120 100 0.001 0.0015 0.002 0.0025 0.003 RL/(RL+R)² (1/Q) The value of gin volt is (mu)d

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Chapter1: Units, Trigonometry. And Vectors
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In the power and energy experiment, the power (PRI) dissipated across the load resistor R is given by the equation:
R,
(R+R¸)²
280
260
y = 102010x - 1E-12
R2 = 1
240
220
200
180
160
..... .... .. . .. ... ...
140
120
100
0.001
0.0015
0.002
0.0025
0.003
RL/(RL+R)² (1/Q)
The value of F in volt is
(mu)d
Transcribed Image Text:In the power and energy experiment, the power (PRI) dissipated across the load resistor R is given by the equation: R, (R+R¸)² 280 260 y = 102010x - 1E-12 R2 = 1 240 220 200 180 160 ..... .... .. . .. ... ... 140 120 100 0.001 0.0015 0.002 0.0025 0.003 RL/(RL+R)² (1/Q) The value of F in volt is (mu)d
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