In the next two problems, the matrix given represents a system of three equations in the variables T, y, and z, and row reduction has already been completed. Give the solution for each. 1 29 18 1 29 -29z + 18 = 29y – 18z + 29 are arbitrary(free) (A) (B) 29z + 18 Y, z is arbitrary(free) -29 (C) 18 (D) no solution 29 %3D -29y – 18 29 29z + 18 %3D (E) (F) -29z + 18 %3D %3D is arbitrary(free) is arbitrary(free) -29y + 18z + 29 are arbitrary(free) -29y + 18 = 29 (G) (H) Y, z is arbitrary(free)
In the next two problems, the matrix given represents a system of three equations in the variables T, y, and z, and row reduction has already been completed. Give the solution for each. 1 29 18 1 29 -29z + 18 = 29y – 18z + 29 are arbitrary(free) (A) (B) 29z + 18 Y, z is arbitrary(free) -29 (C) 18 (D) no solution 29 %3D -29y – 18 29 29z + 18 %3D (E) (F) -29z + 18 %3D %3D is arbitrary(free) is arbitrary(free) -29y + 18z + 29 are arbitrary(free) -29y + 18 = 29 (G) (H) Y, z is arbitrary(free)
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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
Transcribed Image Text:In the next two problems, the matrix given represents a system of three equations in
the variables T, y, and z, and row reduction has already been completed. Give the
solution for each.
1
29
18
1
29
-29z + 18
= 29y – 18z + 29
are arbitrary(free)
(A)
(B)
29z + 18
Y, z
is arbitrary(free)
-29
(C)
18
(D) no solution
29
%3D
-29y – 18
29
29z + 18
%3D
(E)
(F)
-29z + 18
%3D
%3D
is arbitrary(free)
is arbitrary(free)
-29y + 18z + 29
are arbitrary(free)
-29y + 18
= 29
(G)
(H)
Y, z
is arbitrary(free)
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