Consider the following two systems. @ (b) -6x+3y=-2 4x + y (1) Find the inverse of the (common) coefficient matrix A of the two systems. A-¹- J-6z+3y=-1 4x + y = 3 (i) Find the solutions to the two systems by using the inverse, i.e. by evaluating A-¹b where b represents the right hand side (i.e. b= b[¹] for system (a) and b for system (b)). Solution to system (a): == Solution to system (b): Note: Enter exact values rather than decimal approximations. For example, Enter elm wim as "[[1/3,2/3], [1,4/3]]" or "(1/3)*[[1,2], [3,4]] rather than "[0.333333,0.666667]. [1, 1.333333]]"

Algebra and Trigonometry (6th Edition)
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ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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Consider the following two systems.
(a)
(b)
A-¹ =
-6x+3y = -2
4z+y
=-4
(1) Find the inverse of the (common) coefficient matrix A of the two systems.
-6x + 3y =
| 4z+y
Solution to system (a): z =
(ii) Find the solutions to the two systems by using the inverse, i.e. by evaluating A-¹b where b represents the right hand side (ie.
b=
=[3¹] for system (a) and b = [] for system (b)).
Solution to system (b): z
= 3
Note: Enter exact values rather than decimal approximations. For example, Enter
M
131
ww/w
as "[[1/3,2/3], [1,4/3]]" or "(1/3)*[[1,2], [3,4]] rather than "[0.333333,0.666667]. [1, 1.333333]]"
Transcribed Image Text:Consider the following two systems. (a) (b) A-¹ = -6x+3y = -2 4z+y =-4 (1) Find the inverse of the (common) coefficient matrix A of the two systems. -6x + 3y = | 4z+y Solution to system (a): z = (ii) Find the solutions to the two systems by using the inverse, i.e. by evaluating A-¹b where b represents the right hand side (ie. b= =[3¹] for system (a) and b = [] for system (b)). Solution to system (b): z = 3 Note: Enter exact values rather than decimal approximations. For example, Enter M 131 ww/w as "[[1/3,2/3], [1,4/3]]" or "(1/3)*[[1,2], [3,4]] rather than "[0.333333,0.666667]. [1, 1.333333]]"
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