In the next chapter, on Gauss's law, we will show that a single infinite, flat, uniformly charged sheet creates an electric field that has a magnitude that is the same everywhere, and that this magnitude is |E| = 0/(20) where σ Q/A, the source charge on the sheet divided by the area of the sheet. As you might expect, the field points due to positively charged sheets points away from the sheet and the field of negatively charged sheets points toward the sheet, and so the field due to a particular sheet points opposite directions on the two sides of that sheet. Consider a set of two such sheets, placed parallel to each other. I have labeled three regions: I to the left of both sheets, II between them, and III to the right of both. Suppose that the sheet on the left has a negative surface charge density of -6.0 C/m² while the sheet on the right has a positive surface charge density of +9.0C/m². 1 |·|· = (a) Draw a diagram of the sheets and show the direction of the individual field created by each of them in each region I, II, and III. Make sure you clearly label which sheet is creating which arrow in your diagram. NOTE that the individual field by one sheet is not affected by the presence of the other sheet. (b) Find the magnitude of each of the fields you drew in part a, above, using the text's results for large plates. (c) Use superposition (the vector sum of the individual fields you have drawn at a given test point) to find the magnitude and direction of the total field in each region.
In the next chapter, on Gauss's law, we will show that a single infinite, flat, uniformly charged sheet creates an electric field that has a magnitude that is the same everywhere, and that this magnitude is |E| = 0/(20) where σ Q/A, the source charge on the sheet divided by the area of the sheet. As you might expect, the field points due to positively charged sheets points away from the sheet and the field of negatively charged sheets points toward the sheet, and so the field due to a particular sheet points opposite directions on the two sides of that sheet. Consider a set of two such sheets, placed parallel to each other. I have labeled three regions: I to the left of both sheets, II between them, and III to the right of both. Suppose that the sheet on the left has a negative surface charge density of -6.0 C/m² while the sheet on the right has a positive surface charge density of +9.0C/m². 1 |·|· = (a) Draw a diagram of the sheets and show the direction of the individual field created by each of them in each region I, II, and III. Make sure you clearly label which sheet is creating which arrow in your diagram. NOTE that the individual field by one sheet is not affected by the presence of the other sheet. (b) Find the magnitude of each of the fields you drew in part a, above, using the text's results for large plates. (c) Use superposition (the vector sum of the individual fields you have drawn at a given test point) to find the magnitude and direction of the total field in each region.
Related questions
Question
Transcribed Image Text:In the next chapter, on Gauss's law, we will show that a single infinite,
flat, uniformly charged sheet creates an electric field that has a magnitude
that is the same everywhere, and that this magnitude is |E| σ/(2€0)
where = Q/A, the source charge on the sheet divided by the area of
the sheet. As you might expect, the field points due to positively charged
sheets points away from the sheet and the field of negatively charged sheets
points toward the sheet, and so the field due to a particular sheet points
opposite directions on the two sides of that sheet.
Consider a set of two such sheets, placed parallel to each other. I have
labeled three regions: I to the left of both sheets, II between them, and
III to the right of both. Suppose that the sheet on the left has a negative
surface charge density of -6.0C/m² while the sheet on the right has a
positive surface charge density of +9.0 C/m².
=
·|·|·
(a) Draw a diagram of the sheets and show the direction of the individual field created by each of
them in each region I, II, and III. Make sure you clearly label which sheet is creating which arrow
in your diagram. NOTE that the individual field by one sheet is not affected by the presence of
the other sheet.
I
=
(b) Find the magnitude of each of the fields you drew in part a, above, using the text's results for
large plates.
|||
(c) Use superposition (the vector sum of the individual fields you have drawn at a given test point)
to find the magnitude and direction of the total field in each region.
Expert Solution
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
This is a popular solution!
Trending now
This is a popular solution!
Step by step
Solved in 4 steps with 1 images
