In the Midpoint Rule for triple integrals we use a triple Riemann sum to approximate a triple integral over a box B, where f(x, y, z) is evaluated at the center (x, y, z) of the box Bijk- Use the Midpoint Rule to estimate the value of the integral. Divide B into eight sub-boxes of equal size. (Round your answer to three decimal places.) I co cos(xyz) dv, where B = {(x, y, z) | 0 ≤ x ≤ 11,0 ≤ y ≤ 11,0 5 2 5 11}
In the Midpoint Rule for triple integrals we use a triple Riemann sum to approximate a triple integral over a box B, where f(x, y, z) is evaluated at the center (x, y, z) of the box Bijk- Use the Midpoint Rule to estimate the value of the integral. Divide B into eight sub-boxes of equal size. (Round your answer to three decimal places.) I co cos(xyz) dv, where B = {(x, y, z) | 0 ≤ x ≤ 11,0 ≤ y ≤ 11,0 5 2 5 11}
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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I got 62.196 but that seems to be wrong same with its negative value

Transcribed Image Text:In the Midpoint Rule for triple integrals we use a triple Riemann sum to approximate a triple integral over a box B, where f(x, y, z) is evaluated at the center (X, Y, ZK) of the box Bijk. Use the Midpoint Rule to estimate the value of the integral. Divide B into eight
sub-boxes of equal size. (Round your answer to three decimal places.)
JJJ
= {(x, y, z) | 0 ≤ x ≤ 11, 0 ≤ y ≤ 11, 0 ≤ z ≤ 11}
cos(xyz) dv, where B =
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