In the methane molecule, CH4, each hydrogen atom is at the corner of a regular tetrahedron with the carbon atom at the center. If one of the C-H is in the direction of A=î + Î +R and an adjacent C-H bond is at the direction B=î-1-R. results to an angular bond of approximately 109° for a static frozen molecule. However, the molecule we can encounter everyday continuously vibrates and interact with the surrounding causing its bond vector to vary slightly. According to a new spectroscopy analysis, the adjacent bond vectors was found to be A= 1.01i + 1.07j + 1.09k B = 0.92i + -1.07j + -1.04k What is the angle (in degrees) between the bonds based on this new data? Note: Only 1% of error is permitted for the correct answer.
In the methane molecule, CH4, each hydrogen atom is at the corner of a regular tetrahedron with the carbon atom at the center. If one of the C-H is in the direction of A=î + Î +R and an adjacent C-H bond is at the direction B=î-1-R. results to an angular bond of approximately 109° for a static frozen molecule. However, the molecule we can encounter everyday continuously vibrates and interact with the surrounding causing its bond vector to vary slightly. According to a new spectroscopy analysis, the adjacent bond vectors was found to be A= 1.01i + 1.07j + 1.09k B = 0.92i + -1.07j + -1.04k What is the angle (in degrees) between the bonds based on this new data? Note: Only 1% of error is permitted for the correct answer.
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![In the methane molecule, CH4, each hydrogen atom is at the corner of a regular tetrahedron with the carbon atom
at the center. If one of the C-H is in the direction of
A=î + Î +R
and an adjacent C-H bond is at the direction
B=î-1-R.
results to an angular bond of approximately 109° for a static frozen molecule.
However, the molecule we can encounter everyday continuously vibrates and interact with the surrounding causing
its bond vector to vary slightly. According to a new spectroscopy analysis, the adjacent bond vectors was found to
be
A= 1.01i + 1.07j + 1.09k
B = 0.92i + -1.07j + -1.04k
What is the angle (in degrees) between the bonds based on this new data?
Note: Only 1% of error is permitted for the correct answer.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F30728c67-7490-41c1-a533-1f2dc6c4116d%2Fdcdf9d46-c6ed-40c1-97db-c039f295320e%2Fqn4jkya_processed.png&w=3840&q=75)
Transcribed Image Text:In the methane molecule, CH4, each hydrogen atom is at the corner of a regular tetrahedron with the carbon atom
at the center. If one of the C-H is in the direction of
A=î + Î +R
and an adjacent C-H bond is at the direction
B=î-1-R.
results to an angular bond of approximately 109° for a static frozen molecule.
However, the molecule we can encounter everyday continuously vibrates and interact with the surrounding causing
its bond vector to vary slightly. According to a new spectroscopy analysis, the adjacent bond vectors was found to
be
A= 1.01i + 1.07j + 1.09k
B = 0.92i + -1.07j + -1.04k
What is the angle (in degrees) between the bonds based on this new data?
Note: Only 1% of error is permitted for the correct answer.
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