In the methane molecule, CH4, each hydrogen atom is at the corner of a regular tetrahedron with the carbon atomat the center. If one of the C-H is in the direction ofA=î + Î +Rand an adjacent C-H bond is at the directionB=î-1-R.results to an angular bond of approximately 109° for a static frozen molecule.However, the molecule we can encounter everyday continuously vibrates and interact with the surrounding causingits bond vector to vary slightly. According to a new spectroscopy analysis, the adjacent bond vectors was found tobeA= 1.01i + 1.07j + 1.09kB = 0.92i + -1.07j + -1.04kWhat is the angle (in degrees) between the bonds based on this new data?Note: Only 1% of error is permitted for the correct answer.

This problem can be solved using the formula for dot product of two vectors.

Answered: In the methane molecule, CH4, each…

Similar questions

The CO molecule loses hv = 0.2690 eV of vibrational energy and gains 0.000479 eV of rotational energy. Hence the energy E that goes into the emitted photon equals 0.2690 eV less 0.000479 eV, or 0.2685 eV. The photon wavelength is?
In the methane molecule, CH4, each hydrogen atom is at the corner of a regular tetrahedron with the carbon atom at the center. If one of the C-H is in the direction of A=I hut + J hut + K hut and an adjacent C-H bond is at the direction B=I hut - J hut - K hut results to an angular bond of approximately 109o for a static frozen molecule. However, the molecule we can encounter everyday continuously vibrates and interact with the surrounding causing its bond vector to vary slightly. According to a new spectroscopy analysis, the adjacent bond vectors was found to be A = 0.93i + 0.91j + 1.09k B = 1.02i + -0.99j + -1.08k What is the angle (in degrees) between the bonds based on this new data?
When an OH molecule undergoes a transition from the n = 0 to the n = 1 vibrational level, its internal vibrational energy increases by 0.463 eV. Calculate the frequency of vibration and the force constant for the interatomic force. (The mass of an oxygen atom is 2.66 * 10-26 kg, and the mass of a hydrogen atom is 1.67 * 10-27 kg.)
please give solution and answer
Compute the line energy of dislocation in fcc, diamond. The shear modulus of carbon is 462 GNm 2. The diameter of carbon atom in diamond is 1.54Å. Answer: 1.46 x 10-³J/m
The number of normal modes of vibration depends on the shape of the molecule, but not on the number of atoms in the molecule. True False
For a certain diatomic molecule, the lowest-energy photon in the vibrational spectrum is 0.17 eV.What is the energy of a photon emitted in a transition from the 5th exited vibrational energy level to the 2nd exited vibrational energy level, assuming no change in the rotational energy?
If a sodium chloride (NaCl) molecule could undergo an n S n - 1 vibrational transition with no change in rotational quantum number, a photon with wavelength 20.0 mm would be emitted. The mass of a sodium atom is 3.82 * 10-26 kg, and the mass of a chlorine atom is 5.81 * 10-26 kg. Calculate the force constant k′ for the interatomic force in NaCl.
Consider a model of a diatomic molecule with pointmass atoms of mass m1 and m2, separated by a distance R. (a) Show that the rotational inertia of the molecule is I= μR2, where the reduced mass μ = m1 m2/(m1 +m2). (b) Compute the rotational inertia of NaCl, which has a bond length of 0.236 nm. Assume the most common isotopes of sodium and chlorine.
In the methane molecule, CH4, each hydrogen atom is at the corner of a regular tetrahedron with the carbon atom at the center. If one of the C-H is in the direction of and an adjacent C-H bond is at the direction . results to an angular bond of approximately 109o for a static frozen molecule. However, the molecule we can encounter everyday continuously vibrates and interact with the surrounding causing its bond vector to vary slightly. According to a new spectroscopy analysis, the adjacent bond vectors was found to be A = 0.93i + 0.91j + 1.09k B = 1.02i + -0.99j + -1.08k
In two dimensions, two metals A and B, have the number density of free electrons in the ratio n₁: n₁ = 1:2 B The ratio of their Fermi energies is (a) 2:3 (b) 1:8 (c) 1:2 (d) 1 : 4