In the least-squares line y -5+ 3x, what is the marginal change in y for each unit change in x?

MATLAB: An Introduction with Applications
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**Question 1: [-/1 Points]**

**DETAILS**

**BBUNDERSTAT11 9.2.002.**

In the least-squares line \( \hat{y} = 5 + 3x \), what is the marginal change in \( \hat{y} \) for each unit change in \( x \)?

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**Explanation:**

The question relates to understanding linear regression, specifically the interpretation of the slope in the least-squares regression equation. The equation given is \( \hat{y} = 5 + 3x \), where:

- \( \hat{y} \) is the predicted value of the dependent variable.
- \( 5 \) is the y-intercept, indicating the value of \( \hat{y} \) when \( x = 0 \).
- \( 3 \) is the slope of the line, representing the marginal change in \( \hat{y} \) for each unit change in \( x \). This means for every one unit increase in \( x \), \( \hat{y} \) increases by 3 units.

There are no graphs or diagrams in this image.
Transcribed Image Text:**Question 1: [-/1 Points]** **DETAILS** **BBUNDERSTAT11 9.2.002.** In the least-squares line \( \hat{y} = 5 + 3x \), what is the marginal change in \( \hat{y} \) for each unit change in \( x \)? [Submit Answer] **Explanation:** The question relates to understanding linear regression, specifically the interpretation of the slope in the least-squares regression equation. The equation given is \( \hat{y} = 5 + 3x \), where: - \( \hat{y} \) is the predicted value of the dependent variable. - \( 5 \) is the y-intercept, indicating the value of \( \hat{y} \) when \( x = 0 \). - \( 3 \) is the slope of the line, representing the marginal change in \( \hat{y} \) for each unit change in \( x \). This means for every one unit increase in \( x \), \( \hat{y} \) increases by 3 units. There are no graphs or diagrams in this image.
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