In the laboratory a student uses a "coffee cup" calorimeter to determine the specific heat of a metal. She heats 18.4 grams of titanium to 98.86°C and then drops it into a cup containing 75.9 grams of water at 23.43°C. She measures the final temperature to be 25.59°C. Assuming that all of the heat is transferred to the water, she calculates the specific heat of titanium to be J/g°C.
In the laboratory a student uses a "coffee cup" calorimeter to determine the specific heat of a metal. She heats 18.4 grams of titanium to 98.86°C and then drops it into a cup containing 75.9 grams of water at 23.43°C. She measures the final temperature to be 25.59°C. Assuming that all of the heat is transferred to the water, she calculates the specific heat of titanium to be J/g°C.
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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When titanium metal at high temperature is dropped in water at lower temperature, titanium will lose heat and that heat will be gained by water.
So heat lose by titanium = Heat gain by water .
So first we can calculate heat gain by water using the formula :
Q = mC∆T
Then we can use this value of heat to calculate heat capacity of titanium .
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