In the laboratory, a general chemistry student measured the pH of a 0.589 M aqueous solution of triethylamine, (C₂H5)3N to be 12.202. Use the information she obtained to determine the K₁ for this base. K(experiment) = Submit Answer Retry Entire Group 9 more group attempts remaining

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In the laboratory, a general chemistry student measured the pH of a 0.589 M aqueous solution of triethylamine, (C₂H₅)₃N, to be 12.202.

Use the information she obtained to determine the Kb for this base.

\[ K_b(\text{experiment}) = \]

**Explanation for Learners:**

To determine the Kb (base dissociation constant) for triethylamine, use the pH value to find the concentration of hydroxide ions (OH⁻) produced. Then use the formula for Kb:

\[ K_b = \frac{[OH^-]^2}{[Base] - [OH^-]} \]

**Steps:**

1. Calculate the pOH from the pH: 
   \[ \text{pOH} = 14 - \text{pH} \]

2. Convert pOH to [OH⁻]:
   \[ [OH^-] = 10^{-\text{pOH}} \]

3. Substitute [OH⁻] and the initial concentration of the base into the Kb equation to solve for Kb.
Transcribed Image Text:In the laboratory, a general chemistry student measured the pH of a 0.589 M aqueous solution of triethylamine, (C₂H₅)₃N, to be 12.202. Use the information she obtained to determine the Kb for this base. \[ K_b(\text{experiment}) = \] **Explanation for Learners:** To determine the Kb (base dissociation constant) for triethylamine, use the pH value to find the concentration of hydroxide ions (OH⁻) produced. Then use the formula for Kb: \[ K_b = \frac{[OH^-]^2}{[Base] - [OH^-]} \] **Steps:** 1. Calculate the pOH from the pH: \[ \text{pOH} = 14 - \text{pH} \] 2. Convert pOH to [OH⁻]: \[ [OH^-] = 10^{-\text{pOH}} \] 3. Substitute [OH⁻] and the initial concentration of the base into the Kb equation to solve for Kb.
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