In the L-R-C circuit pictured the source provides a voltage v (f) = 172 V cos (120 rad/s t +1 rad). 0.22 mF 15Q 0.12 H Calculate (in amps) the maximum current in the circuit at resonance. ww
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A: RLC SERIES CIRCUIT.
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- Find the differential equation corresponding to the following RLC circuit in fig. when L = 0.5 H, R = 3 0, C = 1/12 F and E(t) = 10sin2t V. Et) = E, sin at (a) I" + 31' +I = 20cos2t (b) I" + 61' + 241 = 20cos2t (c) I" + 6I' + 6I = -20cos2t (d) I" + 61' + 241 = 10cos2t (e) I" + 61' + 241 = 10sin2tConsider the RLC series circuit shown in the figure below where R = 420Ω, L = 75 mH, and C = 0.750 µF. The current in the circuit is given byi(t) = I cos[(9050 rad/s)t], where I is the amplitude current. Find the phaseshift between the source voltage relative to the current in the circuit.In a certain series RLC circuit, Irms = 9.00 A, ΔVrms = 155 V, and the current leads the voltage by 31.0°.
- The I vs t graph shown below is for an LR circuit with a battery. 1(A) 3. 2 1. 9 18 27 36 45 54 63 72 81 90 t(s) Determine the time constant of the LR circuit. TH If L9 H, determine R. R = Ω MYUse the information given in the figure for the series RCL circuit to determine the phase angle between the current and the voltage. 60.0 Hz +90° O Zero degrees O +5.3° -84° 0.035 H -9.6° 1.75 X 10 F HH 150 2.The I vs t graph shown below is for an LR circuit with a battery. I (A) 18 13.5 Determine the tim e constant of the LR circuit. %3D If L = 8 H, determine R. 9. R = 4.5 t (s) 10 20 30 40 50 60 70 80 90 100
- In an RLC circuit, the resistance R does NOT change with frequency. Why would VR change with frequency(consider other factors in the circuit).4, 6Refering to the figure (AC bridge which used to calculate the unknown capacitor): if Lx =50 cm and Cs =1000μF, Cx1 =250µF then CX2 equal to : Answer Cx1 AC D Cx2 12 Lx Oscilloscope Ls 1 LS 12 wwwwwww B a. 1500 µF b. 750 μF C. 1500 pF d. 667 nF