In the interface between sediment and water around a deep lake bottom, dissolved oxygen (DO) is usually low. Under such a condition, iron and sulfur typically exist in their reduction forms (i.e. Fe2+ and S2-).  Fe2+ and S2- can readily react with each other to produce ferrous sulfide (FeS), which is a black solid substance and finally settles down into the sediments at the lake bottom. The solubility product constant (i.e. equilibrium constant) of FeS is 8 x 10-9. At a chemical equilibrium state, what is the concentration of S2- in the water nearby the sediments if Fe2+ concentration in water is 10 - 4 M.

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In the interface between sediment and water around a deep lake bottom, dissolved oxygen (DO) is usually low. Under such a condition, iron and sulfur typically exist in their reduction forms (i.e. Fe2+ and S2-).  Fe2+ and S2- can readily react with each other to produce ferrous sulfide (FeS), which is a black solid substance and finally settles down into the sediments at the lake bottom.

The solubility product constant (i.e. equilibrium constant) of FeS is 8 x 10-9. At a chemical equilibrium state, what is the concentration of S2- in the water nearby the sediments if Fe2+ concentration in water is 10 - 4 M.

Expert Solution
Step 1

Given:

Solubility product constant (Ksp) FeS  = 8 x 10-9

Concentration of Fe2+ = 10- 4 M

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