In the inner region between the two capacitor plates, the electric fields due to the two charged plates are zero. a) True b) False
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In the inner region between the two capacitor plates, the electric fields due to the two charged plates are zero.
a) True
b) False
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- Assume that a negative charge is placed on the top plate of a capacitor. A positive charge is placed on the bottom plate. What is the magnitude of the electric field E between the plates?proton A proton traveling in the - x direction approaches a capacitor consisting of two large, oppositely charged metal plates. The circular plates are 6.1 cm apart and each has a radius of 3.4 m. Each plate has a charge |Q| = 9.0 x 10° C. The left plate is positively charged. The proton enters through the capacitor through a small hole in one of the plates at location A with a speed of 4.6 x 104 m/s. What is the speed of the proton, in m/s, when it exits through a small hole at location B?-A ZE The potential difference between the accelerating plates of a TV set is about 30 kV. If the distance between the plates is 1.3 cm, find the magnitude of the uniform electric field in the region between the plates. N/C
- A parallel plate capacitor with a charge of +/-177nC has square plates length L=20.0cm across on each side. The plates are separated by a distance d=10.0cm. A positive +4.0microC point charge is held in place halfway between each plate on the right-most edge of the capacitor. While solving this problem ignore any distortion of the capacitor's electric field along its edges. A) What is the magnitude and direction of the capacitor's electric field at point P, which is midway between the plates and on the left-most edge of the capacitor B) What is the magnitude and direction of the electric field due to the +4.0 microC point charge at point P. C) What is the magnitude and direction of the net electric field at point PQUESTION 10 What is the electric-field strength between the identical, rectangular, conducting plates of a parallel-plate capacitor in which the charge on the plates is + 5.0 pC? Assume that each plate is 4.0 cm long and 3.0 cm wide. a. 390 N/C b. 150 N/C C. 230 N/C d. 310 N/C e. 470 N/CThe figure shows an electron entering a parallel-plate capacitor with a speed of 5.7×106 m/s. The electric field of the capacitor has deflected the electron downward by a distance of 0.618 cm at the point where the electron exits the capacitor. (Figure 1) Figure V + + + -2.25 cm- + + É + + + < 1 of 1 0.618 cm + Part A Find the magnitude of the electric field in the capacitor. 15| ΑΣΦ 3 E- 3662.75 ! Your answer should not contain commas. No credit lost. Try again. Part B Submit Previous Answers Request Answer www ||| ΑΣΦ v=6.36• 106 Submit Find the speed of the electron when it exits the capacitor. Provide Feedback www. ? Previous Answers Request Answer ? N/C m/s X Incorrect; Try Again; 29 attempts remaining Review your calculations and make sure you round to 3 significant figures in the last step.
- View Policies Current Attempt in Progress A capacitor is constructed of two concentric conducting cylindrical shells. The radius of the inner cylindrical shell is 2.35 x 103 m, and that of the outer shell is 2.47 x 10 m. When the cylinders carry equal and opposite charges of magnitude 2.0 x 10 10 C, the electric field between the plates has an average magnitude of 3.9 x 10 V/m and is directed radially outward from the inner shell to the outer shell. Determine (a) the magnitude of the potential difference between the cylindrical shells and (b) the capacitance of this capacitor. +] Cylindrical capacitor (end view)A parallel-plate capacitor filled with air has plates of area 6.5×10−3 m2 and a separation of 0.32 mm. a) Find the magnitude of the charge on each plate when the capacitor is connected to a 11-V battery. (Q = ? nC) b) Why does answer A decrease if the seperation between the plates increases? c) Calculate the magnitude of the charge on the plates if the separation is 0.90 mm. (Q = ? nC)