In the image you see a sphere rolling down an inclined plane. Rolling without slipping. Is the weight (mg) producing any torque? Select the correct answer. mg O No OYes 1P
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A: See below
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- What constant angular acceleration is required to reduce an object's angular velocity from 36.1 rad/s to 14.9 rad/s over 14 revolutionson s page An arm swings from neutral (0 deg) to 61.3 deg flexion and then back 39.6 deg. Calculate the angular distance op in radians to 2 decimal places. Answer: Check pe here to search E C R F E T B H N U M K K N O P L 3°C Mostly cloudy ^4 # Next page 17:00 01/12/2023 ? 0r = 1.8 mF = 9.2 NFind torque. Indicate both magnitude, including units, and directon
- Answer the question in full details, thank you very much, Answer on the correct significant figures:, and the final answer is not 307.12 rad/s^2 or 310 rad/s^2: A uniform, solid 2.5 kg cylinder can rotate about an axis through its center at O. The forces applied are : F1 =45N, F2 =4.3N, F3 = 5.5N,and F4 = 4.8 N. Also, R1 = 10. cmand R3 = 4.2cm. Find the magnitude (in rad/s^2) and direction (+ denotes counterclockwise and — denotes clockwise) of theangular acceleration of the cylinder.Determine the moment of inertia and the product of ineria for the area ifor the figure above with respect to new centroial axex obtained by rotating the x and y axes 30o counterclockwise. Answer: Ix’= 2.12x106 mm4, Iy’ = 8.28x106 mm4, and Ix’y’ = 0.532x106 mm4Q18. Given the net torque of the system, find the angular acceleration for the 70N system of three particle masses. The radius from the axis of rotation is 12 m and the masses are equidistant. Assuming a constant acceleration, what would the Skg 1kg angular velocity be after 5 seconds? How many revolutions will be completed after 20 seconds with constant acceleration? (a=-1.1 rad/s; w=5.5 rad/s; use 0=wot + ½ at and covert radians to revolutions= 220 rad = 35 rev) 2kg 15N
- If a flywheel is initially moving at an angular velocity Wi = 10 rad/s and accelerates to a final angular velocity Wf = 400 rad/s in a time of 3 seconds, calculate: a.) the angular acceleration (alpha = a) b.) the angular displacement (theta)A 2.30 kg solid, uniform disk of radius 0.140 m is released from rest at point A in the figure below, its center of gravity a distance of 1.70 m above the ground. The disk rolls without slipping to the bottom of an incline and back up to point B where it is launched vertically into the air. The disk then rises to its maximum height hmay at point C. HINT C 1.70 m hmax B 10.400 m (a) At point B, find the disk's translational speed v. (in m/s). X m/s (b) At point B, find the disk's rotational speed wa (in rad/s). rad/s (c) At point C, find the disk's rotational speed w. (in rad/s). rad/s (d) At point C, find the maximum height hmax of the disk's center of gravity (in m).A dentist causes the bit of a high speed drill to accelerate from an angular speed of 1.76e4 rad/s to an angular speed of 3.71e4 rad/s. In the process, the bit turns through 1.62e4 rad.Assuming a constant angular acceleration, how long would it take the bit to reach its maximum speed of 8.42e4 rad/s starting from rest.
- A potter is shaping a bowl on a a potter’s wheel. The wheel rotaes at a constant angular speed. The frictional force between her hands and the clay is 2.25 N. How large is the torque she produces on the wheel if the diameter of the bowl is 14 cm.A constant torque of 25 N.m is apllied to a grindstone whose moment of inertia is 0.125kg.m^2. What is the angular speed (in rad/s) after the grindstone has made 10 revolutions? (Neglect friction)A point on the rim of a wheel moves with a velocity of 95 feet per second. Find the angular velocity of the point if the diameter of the wheel is 5 feet. 19 rad/sec. 38 rad/sec. 475 rad/sec.