In the Hall-Heroult process, a large electric current is passed through a solution of aluminum oxide (Al,0,) dissolved in molten cryolite (Na, AlF), resulting in the reduction of the Al,0, to pure aluminum. Suppose a current of 940. A is passed through a Hall-Heroult cell for 71.0 seconds. Calculate the mass of pure aluminum produced.
In the Hall-Heroult process, a large electric current is passed through a solution of aluminum oxide (Al,0,) dissolved in molten cryolite (Na, AlF), resulting in the reduction of the Al,0, to pure aluminum. Suppose a current of 940. A is passed through a Hall-Heroult cell for 71.0 seconds. Calculate the mass of pure aluminum produced.
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Transcribed Image Text:In the Hall-Heroult process, a large electric current is passed through a solution of aluminum oxide (Al,0,) dissolved in molten cryolite (Na, AlF), resulting
in the reduction of the Al,0, to pure aluminum.
Suppose a current of 940. A is passed through a Hall-Heroult cell for 71.0 seconds. Calculate the mass of pure aluminum produced.
Be sure your answer has a unit symbol and the correct number of significant digits.
Expert Solution

Step 1
we will apply the combined Faraday's law
W = (Q*M )/F*n
W = weight of mass in grams
Q = quantity of electricity passed
M = molar mass of metal
t = time of electricity passed
F = 1 Faraday = 96500C
n = valency of metal
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