In the Hall-Heroult process, a large electric current is passed through a solution of aluminum oxide (Al,02) dissolved in molten cryolite (Na, AIF6), resulting in the reduction of the Al,O, to pure aluminum. Suppose a current of 710. A is passed through a Hall-Heroult cell for 56.0 seconds. Calculate the mass of pure aluminum produced. Round your answer to 3 significant digits. Also, be sure your answer contains a unit symbol. ロロ

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In the Hall-Heroult process, a large electric current is passed through a solution of aluminum oxide (Al,03) dissolved in molten cryolite
(Na, AIF6), resulting in the reduction of the Al,O, to pure aluminum.
Suppose a current of 710. A is passed through a Hall-Heroult cell for 56.0 seconds. Calculate the mass of pure aluminum produced.
Round your answer to 3 significant digits. Also, be sure your answer contains a unit symbol.
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Transcribed Image Text:In the Hall-Heroult process, a large electric current is passed through a solution of aluminum oxide (Al,03) dissolved in molten cryolite (Na, AIF6), resulting in the reduction of the Al,O, to pure aluminum. Suppose a current of 710. A is passed through a Hall-Heroult cell for 56.0 seconds. Calculate the mass of pure aluminum produced. Round your answer to 3 significant digits. Also, be sure your answer contains a unit symbol. Explagation Check O2021 McGraw-Hill Education. All Rights Reserved. Terms of Use Privacy I Acces MAY 6.
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