- In the given figure, the maximum bending moment at the fixed end of the cantilever caused by the UDL is M. The bending moment at a section 1/5 from the free end is w/m man 10000 SM 1/5-1 ➜

Q: Tension arrows are always indicated by an arrow from the pin. O close O away

A: Note:- As per our guideline, we are supposed to answer only the first question. Pinned joint:- A pin…

Q: The beam cross-section shown below has 90 kip-ft of bending moment applies to it. calculate the…

A: Maximum bending moment (M) = 90 kip-ft Determine the maximum compressive bending stress about…

Q: Nonprismatic Beams veered cantilever beam AB of length L has square cross sections and supports a…

A:

Q: The cantilever steel beam as shown below has the rectangular cross section shown, determine the…

A: The given data is: E=200 GPa I=(bh3)/12 I=(200*3503)/12 I=714.58*106

Q: The center of gravity of the 800N highway sign is at point G. It has been determined that it can…

A:

Q: 1. Calculate the critical buckling load Per for the rigid bar AB shown below: P B C Α A lo 10 ft 30…

A: Given Data Determine the critical buckling load (Pcr) for the rigid bar AB.

Q: The cantilevered W530 x 150 beam shown is subjected to a 7.5-kN force F applied by means of a welded…

A: Given:- The cantilevered beam W530×150 beam is given  The magnitude of the force applied = 7.5 kN…

Q: For the portal frame shown in the given figure, the shear equation is B 4 m C 4 m EI = Constant 4 m…

A: Here ,portal frame is given, And we have to find shear equation. Column AB length is 4 metre. Column…

Q: If the beam is subjected to an internal moment of M = 30 kN-m determine the compressive bending…

A:

Q: 12. An aluminium (E = 70 GPa) column built into the ground has length, L = 3.0 m, and is under axial…

A:

Q: 4 - A rectangular block is loaded with a 180 kN axial force and a moment M, as shown in the figure.…

A: Given data: Cross section of column, 100 mm×60 mm Axial load, P=180 kN Maximum allowable tensile…

Q: A simply supported beam of uniform flexure rigidity is loaded as shown in the given below. The…

A: Given data, to find the rotation of the end A

Q: A rigid bar AB, pinned at end A, is supported by a wire CD and loaded by a force P end B as shown in…

A: Given – E = 210 Gpa Vertical deflection (delta) = 6mm Dia of wire(d) = 5mm Moment about A = P x AB =…

Q: Both sections are made of steel with E-200 GPa. The gap between the bottom of the metal bar and the…

A: Given data: Length of section AB, L1=300 mm Length of section BC, L2=300 mm Area of section AB,…

Q: Iso, determine the maximum fiber stress and the stress in a fiber 100mm from the top of the eam at…

A: Shear force and bending moment at the section is important for the structure to detemine the tensile…

Q: For the truss shown in the figure, P₁-12.7 kN and P₂-9.2 kN. Find the force in member AF in units of…

A:

Laws of Equilibrium

A body is said to be in equilibrium if the system of forces acting on the body tends to keep the body at rest, in other words, there is no translation motion or net torque on the body. Under such conditions, the equilibrium conditions are to be applied to analyze the condition. The branch of mechanics that deals with this condition is known as 'statics'. Under equilibrium, there are no net forces on the body.