In the given cable system Determine the maximum Horizontal load ,w KN/m that the system can hold given the cable diameter = 18.75 mm and the allowable tensile strength of the cable ,6 = 1750 MPa. Determine the value of Ti = KN, in the Pulley at A given the details in the diagram above. What will be the volume of the Dead man's Load in D, if the unit weight of concrete is 23.5 KN/m3 .Vol.0f concrete = m3.

In the given cable system Determine the maximum Horizontal load ,w KN/m that the system can hold given the cable diameter = 18.75 mm and the allowable tensile strength of the cable ,6 = 1750 MPa. Determine the value of Ti = KN, in the Pulley at A given the details in the diagram above. What will be the volume of the Dead man's Load in D, if the unit weight of concrete is 23.5 KN/m3 .Vol.0f concrete = m3.

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Concept explainers

Cables

Cables are collections of wires, alternatively referred to as a cord, connector, or plug. They are one or more wires covered in a plastic covering that allows for the transmission of power or data between devices. The earliest use of recognizable electrical cable was the early commercialized telegraph lines. These were iron-made and tedious to produce and install cabling.

Question

100%

KN/m
2.00 m
3.50 m
Cable Diameter = 18.75 mm
Allowable Stress in Cable = 1750 MPa
12.00 m
6.062 m
120.00 m
Ba 52.619
M-0.325
3.50m
T= TA
T1
T= TA
Detalls at A
6.062 m
DETAILS @ A
In the given cable system Determine the maximum Horizontal load ,w =
can hold given the cable diameter = 18.75 mm and the allowable tensile strength of the cable ,6 = 1750 MPa. Determine
the value of T1 =
volume of the Dead man's Load in D, if the unit weight of concrete is 23.5 KN/m3.Vol.0f concrete =
KN/m that the system
KN, in the Pulley at A given the details in the diagram above. What will be the
m3.

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Given data:

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Calculating T1, weight of concrete block(dead load) and volume of block:

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Calculating applied load udl(w):

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Conclusion:

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