In the game of roulette, a player can place a $9 bet on the number 16 and have a 38 probability of winning. If the metal ball lands on 16, the player gets to keep the $9 paid to play the game and the player is awarded an additional $315. Otherwise, the player is awarded nothing and the casino takes the player's $9. Find the expected value E(x) to the player for one play of the game. If x is the gain to a player in a game of chance, then E(x) is usually negative. This value gives the average amount per game the player can expect to lose. The expected value is S (Round to the nearest cent as needed.)
In the game of roulette, a player can place a $9 bet on the number 16 and have a 38 probability of winning. If the metal ball lands on 16, the player gets to keep the $9 paid to play the game and the player is awarded an additional $315. Otherwise, the player is awarded nothing and the casino takes the player's $9. Find the expected value E(x) to the player for one play of the game. If x is the gain to a player in a game of chance, then E(x) is usually negative. This value gives the average amount per game the player can expect to lose. The expected value is S (Round to the nearest cent as needed.)
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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![In the game of roulette, a player can place a $9 bet on the number 16 and have a 2. probability of winning. If the metal ball lands on 16, the player gets to keep the $9
paid to play the game and the player is awarded an additional $315. Otherwise, the player is awarded nothing and the casino takes the player's $9. Find the expected
value E(x) to the player for one play of the game. If x is the gain to a player in a game of chance, then E(x) is usually negative. This value gives the average amount per
game the player can expect to lose.
The expected value is $
(Round to the nearest cent as needed.)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F93f7e035-997e-4eef-8bc0-8423f2674051%2Fc76ebd29-61a2-4867-9e75-adf0f68aef60%2F1jfhpnr_processed.png&w=3840&q=75)
Transcribed Image Text:In the game of roulette, a player can place a $9 bet on the number 16 and have a 2. probability of winning. If the metal ball lands on 16, the player gets to keep the $9
paid to play the game and the player is awarded an additional $315. Otherwise, the player is awarded nothing and the casino takes the player's $9. Find the expected
value E(x) to the player for one play of the game. If x is the gain to a player in a game of chance, then E(x) is usually negative. This value gives the average amount per
game the player can expect to lose.
The expected value is $
(Round to the nearest cent as needed.)
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