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In the game of roulette, a player can place a $7 bet on the number 33 and 1 have a probability of winning. If the metal ball lands on 33, the player 38 gets to keep the $7 paid to play the game and the player is awarded an additional $245. Otherwise, the player is awarded nothing and the casino takes the player's $7. Find the expected value E(x) to the player for one play of the game. If x is the gain to a player in a game of chance, then E(x) is usually negative. This value gives the average amount per game the player can expect to lose. ... The expected value is $ (Round to the nearest cent as needed.)

In the game of roulette, a player can place a $7 bet on the number 33 and 1 have a probability of winning. If the metal ball lands on 33, the player 38 gets to keep the $7 paid to play the game and the player is awarded an additional $245. Otherwise, the player is awarded nothing and the casino takes the player's $7. Find the expected value E(x) to the player for one play of the game. If x is the gain to a player in a game of chance, then E(x) is usually negative. This value gives the average amount per game the player can expect to lose. ... The expected value is $ (Round to the nearest cent as needed.)

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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In the game of roulette, a player can place a $7 bet on the number 33 and 1 have a probability of winning. If the metal ball lands on 33, the player 38 gets to keep the $7 paid to play the game and the player is awarded an additional $245. Otherwise, the player is awarded nothing and the casino takes the player's $7. Find the expected value E(x) to the player for one play of the game. If x is the gain to a player in a game of chance, then E(x) is usually negative. This value gives the average amount per game the player can expect to lose. The expected value is $ (Round to the nearest cent as needed.)
Transcribed Image Text:In the game of roulette, a player can place a $7 bet on the number 33 and 1 have a probability of winning. If the metal ball lands on 33, the player 38 gets to keep the $7 paid to play the game and the player is awarded an additional $245. Otherwise, the player is awarded nothing and the casino takes the player's $7. Find the expected value E(x) to the player for one play of the game. If x is the gain to a player in a game of chance, then E(x) is usually negative. This value gives the average amount per game the player can expect to lose. The expected value is $ (Round to the nearest cent as needed.)
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