In the following reaction, oxygen is the excess reactant. (8 points) SiCl4 + O2 → SiO2 + Cl2 The table shows an experimental record for the above reaction. Trial Starting Amount of SiCl4 Starting Amount of O2 Actual Yield of SiO2 1 150 g 200 g 49.2 g 2 75 g 50 g 25.2 g Calculate the percentage yield for SiO2 for Trial 1. Also, determine the leftover reactant for the trial. Show your work. Based on the percentage yield in Trial 2, explain what ratio of reactants is more efficient for the given reaction.
In the following reaction, oxygen is the excess reactant. (8 points) SiCl4 + O2 → SiO2 + Cl2 The table shows an experimental record for the above reaction. Trial Starting Amount of SiCl4 Starting Amount of O2 Actual Yield of SiO2 1 150 g 200 g 49.2 g 2 75 g 50 g 25.2 g Calculate the percentage yield for SiO2 for Trial 1. Also, determine the leftover reactant for the trial. Show your work. Based on the percentage yield in Trial 2, explain what ratio of reactants is more efficient for the given reaction.
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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In the following reaction, oxygen is the excess reactant. (8 points)
SiCl4 + O2 → SiO2 + Cl2
The table shows an experimental record for the above reaction.
Trial | Starting Amount of SiCl4 | Starting Amount of O2 | Actual Yield of SiO2 |
---|---|---|---|
1 | 150 g | 200 g | 49.2 g |
2 | 75 g | 50 g | 25.2 g |
- Calculate the percentage yield for SiO2 for Trial 1. Also, determine the leftover reactant for the trial. Show your work.
- Based on the percentage yield in Trial 2, explain what ratio of reactants is more efficient for the given reaction.
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