In the following reaction, determine whether the alkyne has been oxidized, reduced, or neither. (Hint: First look at each carbon atom separately and then look at the net change the alkyne as a whole.) Try to determine the answer without calculating oxidation states and then use the calculations to see if your intuition was correct. H2SO4, H2O H9SO4 O The first carbon atom (with two added bonds to O) has been oxidized and the second carbon atom (with two added bonds to H) has also been oxidized. Overall, the alkyne has been oxidized. The first carbon atom (with two added bonds to 0) has been reduced and the second carbon atom (with two added bonds to H) has also been reduced. Overall, the alkyne has been reduced. The first carbon atom (with two added bonds to O) has been oxidized and the second carbon atom (with two added bonds to H) has been reduced. Overall, the alkyne doe not undergo a net change in oxidation state and is, therefore, neither reduced nor oxidized. The first carbon atom (with two added bonds to O) has been reduced and the second carbon atom (with two added bonds to H) has been oxidized. Overall, the alkyne doe not undergo a net change in oxidation state and is, therefore, neither reduced nor oxidized.
In the following reaction, determine whether the alkyne has been oxidized, reduced, or neither. (Hint: First look at each carbon atom separately and then look at the net change the alkyne as a whole.) Try to determine the answer without calculating oxidation states and then use the calculations to see if your intuition was correct. H2SO4, H2O H9SO4 O The first carbon atom (with two added bonds to O) has been oxidized and the second carbon atom (with two added bonds to H) has also been oxidized. Overall, the alkyne has been oxidized. The first carbon atom (with two added bonds to 0) has been reduced and the second carbon atom (with two added bonds to H) has also been reduced. Overall, the alkyne has been reduced. The first carbon atom (with two added bonds to O) has been oxidized and the second carbon atom (with two added bonds to H) has been reduced. Overall, the alkyne doe not undergo a net change in oxidation state and is, therefore, neither reduced nor oxidized. The first carbon atom (with two added bonds to O) has been reduced and the second carbon atom (with two added bonds to H) has been oxidized. Overall, the alkyne doe not undergo a net change in oxidation state and is, therefore, neither reduced nor oxidized.
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Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Transcribed Image Text:In the following reaction, determine whether the alkyne has been oxidized, reduced, or neither. (Hint: First look at each carbon atom separately and then look at the net change for
the alkyne as a whole.) Try to determine the answer without calculating oxidation states and then use the calculations to see if your intuition was correct.
H2SO4, H2O
H9SO4
The first carbon atom (with two added bonds to O) has been oxidized and the second carbon atom (with two added bonds to H) has also been oxidized. Overall, the alkyne
has been oxidized.
The first carbon atom (with two added bonds to O) has been reduced and the second carbon atom (with two added bonds to H) has also been reduced. Overall, the alkyne
has been reduced.
The first carbon atom (with two added bonds to O) has been oxidized and the second carbon atom (with two added bonds to H) has been reduced. Overall, the alkyne does
not undergo a net change in oxidation state and is, therefore, neither reduced nor oxidized.
The first carbon atom (with two added bonds to O) has been reduced and the second carbon atom (with two added bonds to H) has been oxidized. Overall, the alkyne does
not undergo a net change in oxidation state and is, therefore, neither reduced nor oxidized.
Expert Solution
Step 1
In the above reaction, Alkyne is being converted to ketone upon hydration with aqueous acid(H2SO4).
The addition of a hydroxyl group to an alkyne causes tautomerization which forms carbonyl. Markovnikov addition of a hydroxyl group to an alkyne to form ketone.
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